Answer please I need help

If its wavelength were doubled, its energy would be If its wavelength were doubled, its energy would be 4E. 2E. 12E. 14E.

ANEK [815]

The wavelength was doubled, and its energy will be increased by 4 times.

looking at the formula

energy $E = MC^2$

also, $c = \lambda \times \nu$

hence it is clear from above that energy is directly proportional to the square of the wavelength.

hence, The wavelength was doubled, and its energy will be increased by 4 times.

<h3>What is Wavelength?</h3>

The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
The term wavelength is occasionally used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

To learn more about wavelength with the given link

brainly.com/question/13533093

#SPJ4

5 0

1 year ago

When steam condenses 1. All of these occur. 2. None of these occur. 3. molecules move closer together. 4. it changes from the ga

True [87]

2. None of these occur

5 0

3 years ago

Read 2 more answers

Which processes cause rocks to be exposed<br> at Earth's surface? SC.7..6.2

seropon [69]

Answer:

weathering

Explanation:

5 0

2 years ago

a bal is launched upward with a velocity of v0 from the edge of a cliff of height D. it reaches a maximum height of H above its

lilavasa [31]

Answer:

D/H =15

Explanation:

We can find first the peak height H, taking into consideration, that at the maximum height, the ball will reach momentarily to a stop.
At this point, we can find the value of H, applying the following kinematic equation:

$v_{f} ^{2} -v_{0} ^{2} = 2* g* H (1)$

If vf=0, if we assume that the positive direction is upwards, we can find the value of H as follows:

$H = \frac{v_{0} ^{2} }{2*g} (2)$

We can use the same equation, to find the value of D, as follows:

$v_{f} ^{2} -v_{1} ^{2} = 2* g* D (3)$

In order to find v₁, we can use the same kinematic equation that we used to get H, but now, we know that v₀ = 0.
When we replace these values in (1), we find that v₁ = -v₀.
Replacing in (3), we have:

$(4*v_{0})^{2} - (-v_{0}) ^{2} = 2* g* D\\ \\ 15*v_{0}^{2} = 2*g*D$

Solving for D:

$D = \frac{15*v_{0} ^{2} }{2*g}$

From (2) we know that H can be expressed as follows:

$H = \frac{v_{0} ^{2} }{2*g}$

⇒ D = 15 * H

$\frac{D}{H} = 15$

3 0

2 years ago

Sarah, who lives in Australia notices that the length of the shadow of the flagpole is getting shorter every day when measured a

Allisa [31]

Answer:

Time zone is one important factor in difference in location and this in turn affects the result of the resolution and rotation of shadow produced from the sun or other illumination.

Therefore someone at a place might see a clear large shadow due to shinny sun reflection and another a small or dull Shadow at same time if the intensity of the sun or lighting source is going down.

Explanation:

The closer a body/object is to a lighting source the larger the shadow it produces, and the farther the body the smaller the shadow produced.

3 0

3 years ago