Answer:
Given that
P = RT/V + a/V²
We know that
H= U + PV
For T= Constant (ΔU=0)
ΔH= ΔU +Δ( PV)
ΔH= Δ( PV)
P = RT/V + a/V²
P V= RT + a/V
dH/dV = d(RT + a/V)/dV
dH/dV = - a/V²
So the expression of dH/dV
b)
In isothermal process
(ΔU=0)
Now by putting the all values
ΔH = 17.06 L.atm
<h3>
Answer:</h3>
AgCl + NaNO₃
<h3>
Explanation:</h3>
- The reaction between silver nitrate and sodium chloride is an example of a double displacement reaction.
- In a double displacement reaction compounds or salts reacts and exchange cations or anions to form new compounds or salts.
- In this case, silver nitrate and sodium chloride exchange anions and cations to form silver chloride and sodium nitrate.
- Therefore, the complete reaction is given by;
AgNO3 + NaCl → AgCl + NaNO₃
- But since silver chloride is a precipitate, the reaction may also be an example of a precipitation reaction.
Answer: 160 m
Explanation: First find time or t using the formula for acceleration:
a = vf - vi / t
So t is equal to:
t = vf - vi / a
= 0 m/s - 20 m/s / -2.5 m/s²
= 8 s
To find the distance use the formula for velocity:
v = d / t
Derive for d:
d = v x t
= 20 m/s x 8 s
= 160 m
Formula for kinetic energy of an object:
KE = 0.5mv²
m is the mass and v is the velocity.
Formula for the work done on a charged object by moving it through a potential difference:
W = ΔVq
ΔV is the potential difference and q is the charge of the object.
To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:
W = KE
Substitute W = ΔVq and KE = 0.5mv²
ΔVq = 0.5mv²
Given values:
q = 1.6×10⁻¹⁹C
m = 9.11×10⁻³¹kg
v = 6.0m/s
Plug in the given values and solve for ΔV
ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²
ΔV = 1.02×10⁻¹⁰V
