3 years ago

Can someone help me with this!!!!

Mathematics

1 answer:

marin [14]3 years ago

6 0

Answer: ok

Step-by-step explanation:

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Write the equation using function notation f(x). then find f(0)<br><br> 2x^2 - 3y = 6

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f(0) = -2$

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$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6$

$\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2}$

$\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6$

$\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3}$

$\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

[ here, y can be replaced with f(x) because y is a function of x ]

$\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

$\large\textsf{Find f(0):}$

$\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2$

$\qquad \tt \rightarrow \: f(0) = 0 - 2$

$\qquad \tt \rightarrow \: f(0) = - 2$

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θ = 67.4°

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