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3 years ago

2

Mathematics

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

16.5 hours

Step-by-step explanation:

The bicycle costs $240. Eva already has $42. She is making $12 per hour.

240 = 12x + 42

Solve for x to find out how many hours Eva needs to work to buy the bicycle.

240 = 12x + 42

240 - 42 = (12x + 42) - 42

198 = 12x

198/12 = (12x)/12

16.5 = x

Eva needs to work 16.5 hours to be able to buy the bikw.

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3 years ago

Help me, Don't spam

Anuta_ua [19.1K]

QuestioN:

A container in the shape of of a frustum of a cone having diameters of its two circular faces as 35 cm and 30 cm and vertical height 14 cm, is completely filled with oil. if each of oil has mass 1.2 g, then find the cost of oil in the container if it costs $ 40 per kg.

${\large{\frak{\pmb{\underline{ Clearly,\:we\: have}}}}}$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:r = \bf\dfrac{30}{2}\:cm=15\:cm$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:R = \bf\dfrac{35}{2}\:cm=17.5\:cm$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:h = 14\:cm$

$\:\:\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━━$

$\:$

${\bold { \underline{\small{Now,}}}}$

$\:\:\large{\ddagger}\underline {\footnotesize{\boxed{\frak{Volume_{(container)}={\frak{\orange{\bigg\{\bf\dfrac{1}{3}\pi (R^2+r^2+Rr)h\bigg\}cu}}}}}}}$

$\:\:$

$\:$

$\sf {\scriptsize\Bigg[\bf\dfrac{1}{3}\times \bf\dfrac{22}{7}\times\Bigg\{\bigg(\dfrac{35}{2}\bigg)^2+(15)^2+\dfrac{35}{2}\times 15\Bigg\}\times 14 \Bigg]cm^3}$

$\:\:$

$\:$

$\sf \:\:\:\:\:\rightarrowtail\: \dfrac{44}{3}\times\bigg(\dfrac{1225}{4}+225+\dfrac{525}{2}\bigg)cm^3$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{44}{3}\times \dfrac{3175}{4}\bigg)cm^3$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{3175 \times 11}{3}\bigg)cm^3$

$\:\:$

$\:$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\small{\underline{\mathcal{\red{Mass\:of\:1\:cm^3\:of\:oil\:=\:1.2\:g }}}}$

$\:\:$

$\:$

$\:\:\:\:\:\:\:\sf \footnotesize{Mass_{(oil\:in\:the\: container)}=\bigg( \dfrac{3175 \times 11}{3}\times1.2 \bigg)\:g}$

$\:\:$

$\:$

$\sf\:\:\:\:\:\:\:\:\rightarrowtail\:\bigg( \dfrac{3175 \times 11}{3}\times\dfrac{12}{10}\times\dfrac{1}{1000}\bigg)\:kg$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\:\dfrac{1397}{100}\:kg\:=13.97\:kg$

$\:\:$

$\:$

$\bf\twoheadrightarrow$ Cost of oil at $40 per kg = $(13.97×40) $\:\:=\:\large{\underline{\mathcal{\purple{\$\:558.80.}}}}$

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3 years ago