I did it on the calculator and the answer is 7.77777777778
        
                    
             
        
        
        
Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x²        (1)
The base area is 2x² m². 
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
 
        
        
        
Answer:
Depending on the shaded area, it will be less than 113 in², so not the last option
Step-by-step explanation:
Area of a circle is A= πr²
if it fits in 12 inch sides, 12 i the diameter and 6 is the radius
A= 3.14(6)²
A= 113 in²
Then, find what the shaded area is