Answer:
two triangles with dimensions of 1 ft by 3 ft and a rectangle with dimensions of 4 ft by 3 ft
Step-by-step explanation:
we know that
A trapezoid can be divided into one rectangle and two triangles
Find the dimensions of rectangle
The base is equal to the minor base of trapezoid
so

The height of rectangle is the same that the height of trapezoid

The dimensions of rectangle are 4 ft by 3 ft
Find the dimensions of triangles
The base of triangles is equal to the semi-difference of the bases of trapezoid
so

The height of triangles is the same that the height of the trapezoid

The dimensions of triangles are 1 ft by 3 ft
therefore
two triangles with dimensions of 1 ft by 3 ft and a rectangle with dimensions of 4 ft by 3 ft
To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
Hey there mate ;)
<h3><u>
Answer:- ( 10 </u>
<u> </u><u> </u><u>
20</u>
<u> </u><u> </u><u>
10)</u></h3>
Explanation:-
As per question, we can solve by splitting 40 into :-

Proof:
● As its told that the second number must be twice the first number , which means 20 should be the double of 10 (Proved)
● Next it is told that the third number must be the same as first number, which means that 10 must be equal to 10, which is true.
So, the answer is <u>(10 20 10)</u>
What is the question ? Do you have a picture of the model?
Multiply the whole number by the denominator (8*40=320) then add it to the numerator (320+21=341).
Then you get 341/40