All categories

3 years ago

I AM IN DESPERATE NEeD OF QUICK HELP PLEASEEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

ANEK [815]3 years ago

4 0

The area is the area of the rectangle minus the semicircle.

The radius is 8 mm, and the length of the rectangle is 16 mm, the diameter.

$8 \times 16 - \frac{3.14 \times {8}^{2} }{2} \\ = 27.52$

27.52 mm²

nekit [7.7K]3 years ago

3 0

27.52 mm2 should be your answer

You might be interested in

How many solutions does this have

RSB [31]

Answer:

one solution

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me with this exercise

Vinil7 [7]

The answer you are looking for is: 
270 $yards^{2}$ 
15*18= 270 
And you have to add the yard square at the end. 
Hope that helps!! 
Have a wonderful day!!

6 0

3 years ago

Please help me with this question

SIZIF [17.4K]

-3/4x+6 < A < 4x
hope this helps

6 0

2 years ago

Which choice is the solution for this system ? 2x − 5y = 14 x + 3 2 y = 5

VashaNatasha [74]

Answer:

The required solution is (5.75,-0.5). It can be written as $(\frac{11}{4},-\frac{1}{2})$ .

Step-by-step explanation:

The given equations are

$2x-5y=14$ .... (1)

$x+\frac{3}{2}y=5$ .... (2)

Multiply the equation (2) by 2.

$2x+3y=10$ .... (3)

Subtract equation (1) from equation (3).

$2x+3y-(2x-5y)=10-14$

$2x+3y-2x+5y=-4$

$8y=-4$

$y=-\frac{1}{2}=-0.5$

Put this value in equation (1).

$2x-5(-0.5)=14$

$2x+2.5=14$

$2x=11.5$

$x=5.75$

Therefore the required solution is (5.75,-0.5). It can be written as $(\frac{11}{4},-\frac{1}{2})$ .

3 0

2 years ago

Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1

weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

$f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})$

This gives

$f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})$

Evaluate the products

$f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})$

Evaluate the like terms

$f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}$

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0

1 year ago