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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

Lapatulllka [165]3 years ago

5 0

Answer:

a fraction bar Is just a division bar, it's c.

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Sin (3x) dx = ?<br> find the integral

AVprozaik [17]

Answer:

$\displaystyle \displaystyle \int {sin(3x)} \, dx = \frac{-cos(3x)}{3} + C$

General Formulas and Concepts:

<u>Calculus</u>

Antiderivatives - Integrals

Integration Constant C

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int{sin(x)} \, dx = -cos(x) + C$

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle \int {sin(3x)} \, dx$

<u>Step 2: Identify Substitution Variables</u>

u = 3x

du = 3dx

<u>Step 3: Integrate</u>

[Integral] Rewrite: $\displaystyle \frac{1}{3}\int {3sin(3x)} \, dx$
[Integral] U-Substitution: $\displaystyle \frac{1}{3}\int {sin(u)} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{3}[-cos(u)] + C$
[Expression] Multiply: $\displaystyle \frac{-cos(u)}{3} + C$
[Expression] Back-Substitute: $\displaystyle \frac{-cos(3x)}{3} + C$

8 0

3 years ago

Shopping at savers mart, Lisa buys her children four shirts and three pairs of pants for $85.50. She returns the next day and bu

natta225 [31]

So you have to make two equations. Let's say x stands for shirts and y stands for pants. 4x+3y=85.50. The second equation would be, 5y=115-3x. Since you need one of them to have x= or y=, you need to change it to that form. y=. Then you do substitution and solve which leaves you with:

Shirts are $7.50
Pants are $18.50

4 0

3 years ago

Need some help im not smart

zlopas [31]

Sure your smart Its just not your subject....School isn't my thing but you put me out into the woods and i could survive weeks with nothing...Lol just find your nitch and be proud of it

6 0

3 years ago

A teacher graded s 27 tests in 3 hours. Do these quantities(number of tests graded in time) vary directly or inversely? Explain.

Gwar [14]

Answer:

directly

Step-by-step explanation:

3 0

3 years ago

The class scores of a history test have a normal distribution with a mean Mu = 79 and a standard deviation Sigma = 7. If Opal’s

e-lub [12.9K]

Using the normal distribution, we got that expression for the z-score of her test score is

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

<h3>What is Normal Probability Distribution?</h3>

it's a type of probability distribution which is symmetric about the mean, it gives data near the mean are more frequent than data far from the mean.

Given that mean = $\mu=79$