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Verizon [17]
3 years ago
10

A cheetah can run 110.352 kilometers per hours. A antelope can run 96.12 kilometers per

Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0

110.352-96.12=14.2320000

slavikrds [6]3 years ago
3 0

Answer:

D. 14.232 Kilometers

Step-by-step explanation:

110.352-96.12 = 14.232

pls give brainliest

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Pls help this is due today
Ira Lisetskai [31]

Answer: 256

Step-by-step explanation:

8x8=64

64x4=256

7 0
2 years ago
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Jenny charges $9.15 an hour to babysit toddlers and $7.45 an hour to babysit school-aged children, If jenny babysat toddlers for
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  She would earn $127.05 dollars for babysitting
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3 years ago
Did the scale factor of 0.75 enlarge reduce or stay the same?
elixir [45]

Answer:

\huge\boxed{\sf Reduces}

Step-by-step explanation:

Since the scale factor of 0.75 is less than 1, So the dilated image is a reduced image.

Thus the scale factor of 0.75 reduces the dilated image.

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
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The price of a smartphone increased from $25 to $40. Find the percent<br> increase
saveliy_v [14]

Answer:60% increase

Source:trust me bro

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3 years ago
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