Answer:
I am assuming you want to know how many total cartons will be used which is about 61 cartons with a remainder of 10 eggs.
Step-by-step explanation:
To solve for this problem we have to divide 742 by 12:
742/12 = 61.833333...
This means that the "whole" number of cartons will be 61
If you want to find the remaining eggs not in decimal form, you have to mulitlpy 12 by 61 and take this number away from 742 to find the remainder:
**Note: 12 * 61 can also be written as 61 * 12
12 * 61 = 732 → 742 - 732 = 10 eggs
I hope this helps!
Answer:
a) 21684
b) 15504
Step-by-step explanation:
a) Distribute the comic books as follows
only to 1 kid one way but we have five kids then 5
to two kids C₂₀,₂ = 20! /2! ( 20-2)! = 20*19 /2 = 190
To three C₂₀,₃ = 20! /3! ( 20 - 3)! = 20*19*18 /6 = 1140
To four C₂₀,₄ = 20 ! / 4! ( 20 - 4 )! = 20*19*18*17 /4*3*2 = 4845
To five C₂₀,₅ = 20! /5! (20 - 5 )! = 20*19*18*17*16/5*4*3*2*1
C₂₀,₅ = 15504
Then total ways of distribution are:
5 + 190 + 1140 + 4845 + 15504 = 21684
b) C₂₀,₅ we know from a that is equal to 15504
Answer:
B
Step-by-step explanation:
it shows every 4 hours, so:
560-336=224
224:4=56 per hour
3/11 divided by 9/13 = 3/11 multiplied by 13/9 = 39/99=13/33
Answer:
17
Step-by-step explanation:
Here in this question for finding the numbers that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively we have to first subtract the remainder of the following. By this step we find the highest common factor of the numbers.
And then the required number is the HCF of the following numbers that are formed when the remainder are subtracted from them.
Clearly, the required number is the HCF of the numbers 398−7=391,436−11=425, and, 542−15=527
We will find the HCF of 391, 425 and 527 by prime factorization method.
391=17×23425=52×17527=17×31
Hence, HCF of 391, 4250 and 527 is 17 because the greatest common factor from all the numbers is 17 only.
So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
Note: - whenever we face such a type of question the key concept for solving this question is whenever in the question it is asking about the largest number it divides. You should always think about the highest common factor i.e. HCF. we have to subtract remainder because you have to find a factor that means it should be perfectly divisible so to make divisible we subtract remainder. because remainder is the extra number so on subtracting remainder it becomes divisible.
