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Slav-nsk [51]
3 years ago
13

You move down 5 units and right 1 unit. You end at (5,-3). Where did you start?

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

ff

Step-by-step explanation:

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prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
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Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

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3 years ago
In a 30-60-90 right triangle, the shorter leg has a length of 4. What is the length of the longer leg? How would I figure this o
iVinArrow [24]

Answer:

use a^2 +b^2=c^2

Step-by-step explanation:


5 0
3 years ago
If x - 2y + z = 5 and -x + 3y - z = 2, then y = ?
jok3333 [9.3K]

Answer:

y=10

Step-by-step explanation:

5 0
3 years ago
Solve the following equation for x, in terms of a and b <br><br> ax= 15+bx
ZanzabumX [31]
Ax=15+bx
ax-bx=15
x(a-b)=15
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Solve the following system of equations.<br> 4x-2y-z=-5<br> x-3y+2z=3<br> 3x+y-2z=-5
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4x - 2y - z = - 5 ______×2x - 3y + 2z = 3 _______×13x + y - 2z = - 5 ______×1
8x - 4y - 2z = - 10x - 3y + 2z = 33x + y - 2z = - 5
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x - 3y + 2z = 3(+) 3x + y - 2z = - 5_____________4x - 2y = - 24x - 2(9/7x + 1) = - 24x - 18/7x - 2 = - 210/7x = 0x = 0
y = 9/7(0) + 1y = 1
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3 0
3 years ago
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