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2 years ago

Divide ₹210 among A and B in the ratio 2:3

Mathematics

2 answers:

il63 [147K]2 years ago

6 0

Answer:

let the ratio be 2x and 3x

now

2x +3x =210

5x=210

x=210÷5

x=42

then

putting value of x in ratios

2x=2 *42 =84

3x=2*42 =126

Ira Lisetskai [31]2 years ago

3 0

Answer:

2:3 when the BRUH A b,.

Step-by-step explanation:

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3 years ago

Hi :) how to do question 7 ?

Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
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PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
After simplyfying the expressions we get finally : -12+8x-8y=0
now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16

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3 years ago

Read 2 more answers

Divide ₹210 among A and B in the ratio 2:3​

Divide ₹210 among A and B in the ratio 2:3