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sattari [20]
3 years ago
6

Square PQRS is transformed as shown on the graph.

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

the answer is a

Step-by-step explanation:

took test and got it right

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I need help on #5 on my summer packet my teacher never taught me this and I need help.
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Answer:

c

Step-by-step explanation:

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GEOMETRY 10TH GRADE NEED HELP ASAP
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\boxed{(6, -3)}

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be (x_{1}, y_{1}), and let point B be (x_{2}, y_{2}).

(-6, 3) → (x_{1}, y_{1}).

(26, -13) → (x_{2}, y_{2}).

Let 5 be n, and 3 be m.

5:3 → n:m

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}).

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) →

(\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) →

(\frac{(5)(-6)+ (3)(26)}{(5)+(3)}, \frac{(5)(3)+ (3)(-13)}{(5) + (3)}) →

(\frac{-30 + 78}{8}, \frac{15+ -39}{8}) →

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→

(\frac{6}{1}, \frac{-3}{1})

→

(6, -3).

Thus the coordinates of B are:

\boxed{(6, -3)}

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