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2 years ago

Square PQRS is transformed as shown on the graph.

Mathematics

1 answer:

Taya2010 [7]2 years ago

5 0

Answer:

the answer is a

Step-by-step explanation:

took test and got it right

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What is the cube root of 27a^12

tino4ka555 [31]

ANSWER

$3{a}^{4 }$

EXPLANATION

The cube root of

$27 {a}^{12}$

$\sqrt[3]{27 {a}^{12} }$

This is the same as:

$(27 {a}^{12} )^{ \frac{1}{3} }$

$( {3}^{3} ({a}^{4})^{3} )^{ \frac{1}{3} }$

$= (3{a}^{4} )^{3 \times \frac{1}{3} }$

$= 3{a}^{4 }$

6 0

3 years ago

Which inequality represents a number n that is less than or equal to 3 but greater than -2?

Kisachek [45]

-2 < n $\leq$ 3

This inequality basically says "-2 is less than n, which is less than or equal to 3".

Mark as brainliest if this helped! :)

5 0

2 years ago

Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m

ch4aika [34]

Answer:

$\ln x+\frac{1}{3}\ln (x^2+1)$

Step-by-step explanation:

Consider the given expression is

$\ln (x\sqrt[3]{x^2+1})$

We need to rewrite the expression as a sum,difference,or multiple of logarithms.

$\ln (x(x^2+1)^{\frac{1}{3}})$ $[\because \sqrt[n]{x}=x^{\frac{1}{n}}]$

Using the properties of logarithm we get

$\ln x+\ln (x^2+1)^{\frac{1}{3}}$ $[\because \ln (ab)=\ln a+\ln b]$

$\ln x+\frac{1}{3}\ln (x^2+1)$ $[\because \ln (a^b)=b\ln a]$

Therefore, the simplified form of the given expression is $\ln x+\frac{1}{3}\ln (x^2+1)$ .

6 0

3 years ago

P is the set of even numbers that are less than 11

ivanzaharov [21]

Is there a restriction that the set must be positive? or whole numbers? Because negative numbers can be even, which makes your set an infinite list of numbers.

Natural numbers: P = {2, 4, 6, 8, 10}

Whole numbers: P = {0, 2, 4, 6, 8, 10}

All real numbers: P = {2n ;n ≤ 5}

6 0

2 years ago

What is the answer of 4x if x=2

Semmy [17]

Answer:

Step-by-step explanation:

4(x)

4(2)

3 0

3 years ago

Read 2 more answers