Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14

<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9

Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
The answer is 43j you just have to add them together
Answer:
c
Step-by-step explanation:
i think it is c bec 1ft is 6m
Hey!
You must divide the amount of money he spent by the amount of money each ticket costs:
32 ÷ 8 = 4
So, Mr. Chen bought 4 tickets.
1. 4 times 6
2. 8 divided by 2
3. 4 squared 2