A. Starts slowly and then accelerates.
Given parameters:
Frequency of the wave = 1520kHz = 1520 x 10³Hz
Unknown:
Wavelength of the radio photon = ?
Energy of the wave = ?
Solution:
The wavelength of any electromagnetic wave can found using the expression below;
C = f x ∧
Where C is the velocity of light = 3 x 10⁸m/s
f is the frequency of the wave
∧ is the wavelength
Since the unknown is ∧, input the known parameters and solve for it;
3 x 10⁸ = 1520 x 10³ x ∧
Wavelength =
Wavelength =
Wavelength = 1.97 x 10²m
ii. Energy of the wave;
Energy of a wave = hf
where h is the planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹
f is the frequency of the wave
Input the parameters and solve;
Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶
= 10.1 x 10⁻²⁸J
The energy of this wave is 10.1 x 10⁻²⁸J
Answer:
n = 1.76
Explanation:
According to the rule of ( n1 sin theta1 = n2 sin theta2 )
we know both angles so we insert them to the law and apply n1 = 1
so 1/2 = n2 sin 62 and we get the final answer