All categories

3 years ago

Eating eggs for breakfast increases grades. What is the constant?

Physics

1 answer:

Feliz [49]3 years ago

6 0

Answer and Explanation:

The answer would be: Breakfast

Breakfast would be the constant of this scenario because this doesn't change. The time of day (for eating eggs) will always be in the morning, so that wouldn't change.

Eating eggs would be the independent variable because you can change this value. This could be a different food or an amount of the food that is being eaten.

The grades would be the dependent variable because the score depends on the eating of eggs.

#teamtrees #PAW (Plant And Water)

I hope this helps!

You might be interested in

How does the kinetic energy of an object relate to its mass and velocity?

Setler [38]

The kinetic energy of an object is directly proportional to its mass, and to the square of its velocity.

5 0

3 years ago

Which statements describe the image produced by a concave lens?check all that apply.

kotegsom [21]

Answer:

The answers are:

A-which is the image is always right side up.

E-the image is virtual

Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..

<h2 />

7 0

4 years ago

Read 2 more answers

A man pulls a sled at a constant velocity across a horizontal snow surface. if a force of 80 n is being applied to the sled rope

balandron [24]

A constant velocity implies the two forces must be equal and opposite.
Friction acts horizontal to the ground, therefore we must find the force applied to the sled rope that acts horizontal to the ground.
Do this by resolving:
Force = 80cos53
The force opposing this is equal, and so also = 80cos53 = 48 N (2 sig. fig.)

3 0

4 years ago

Read 2 more answers

The mass of the earth is 5.96/10kg^24. The radius of the earth is approximately 6.37x10^6 calculate the force of gravity

n200080 [17]

<h2>Answer:g=9.79 $ms^{-2}$ ,A object of mass $m$ at the surface of earth experiences a force $mg$ </h2>

Explanation:

Let $M$ be the mass of earth.

Let $R$ be the radius of earth.

Let $G$ be the universal gravitational constant.

Given,

$M=5.96\times 10^{24}Kg$

$R=6.37\times 10^{6}m$

$G=6.67259 \times 10^{-11}$ $Nm^{2}Kg^{-2}$

Let $g$ be the acceleration due to gravity.

Then, $g=\dfrac{GM}{R^{2}}$

$g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}$

$g=9.79ms^{-2}$

A object of mass $m$ at the surface of earth experiences a force $mg$

3 0

3 years ago

Why is heat acclimatization important?

kicyunya [14]

Answer:

Heat acclimatization :

It is the biological adaptations or we can say that it coverts according to the present environment.It also reduce the strain and maintain the normal temperature and heart rate.Heat acclimatization also increase the comfort and reduce all the mental strain and also protect out liver ,muscles ,kidneys and brain fro the injury.

5 0

3 years ago