Question

Someone help me pls

Answer 1

Area of Rectangle: Width × Length

$2(a + 5) \times 3(a + 4)$

Distribute 2 in a+5 and 3 in a+4 first.

$(2a + 10) \times (3a + 12)$

Then we multiply both polynomial.

$(2a \times 3a) + (2a \times 12) + (10 \times 3a) + (10 \times 12) \\ 6 {a}^{2} + 24a + 30a + 120$

$6 {a}^{2} + 54a + 120$

Therefore the answer is 6a²+54a+120

Answer 2

Answer:

Area of rectangle = length × Width

= [ 3 × ( a+4) ] × [ 2 ( a+5 ) ]

= [ 3a + 12 ] × [ 2a + 10 ]

= 12a + 30a + 24a + 120

=

$6 {a}^{2} + 54a + 120$