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Bezzdna [24]
3 years ago
11

2. How many solutions does the below system of equations have?

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0
Y=5x-4

3y=15x-8
3(5x-4)=15x-8
15x-12=15x-8
??

Therefore, there is no solution.
S_A_V [24]3 years ago
4 0
No solution because the slopes end up being equal and they become parallel and then they won’t intersect
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Ella has a box of chocolate candies. She gives 1/3 of the candies to her sister, 4 to her brother, and eats the remaining 12 can
tatyana61 [14]

Answer:

24 candies originally

Step-by-step explanation:

Add the 4 to how many you had left, then think about that number, 16, and what goes into 16 evenly 2 times? 8 and originally she gave away 1/3 of the box and if you were to add another 8 to the box it would be 24 divided by 1/3, -,-4,= 12.

3 0
3 years ago
. Jordan is inviting 8 friends to his party. He wants to give each friend 2 maracas and have 2 for himself. Maracas come in boxe
Elenna [48]

Answer:

3 boxes of maracas

Step-by-step explanation:

9 x 2 = 18

18 ÷ 6 = 3 boxes of maracas

8 0
3 years ago
Read 2 more answers
(Geometry) The answers are x = 15 and y = 9 but I don't know how. Help me understand this
Kryger [21]

Check the picture below.

\bf \stackrel{\measuredangle DAC}{4y+2x}~~=~~\stackrel{\measuredangle BCA}{9y-x}\implies 2x=5y-x\implies 3x=5y\implies \boxed{x=\cfrac{5y}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\measuredangle DAB}{[(4y+2x)+35]}~~+~~\stackrel{\measuredangle ADC}{5x+4}~~=~~180\implies 4y+2x+5x+39 = 180 \\\\\\ 4y+7x+39=180\implies 4y+7x=141\implies \stackrel{\textit{substituting "x"}}{4y+7\left( \boxed{\cfrac{5y}{3}} \right)} = 141

\bf 4y+\cfrac{35y}{3}=141\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3\left( 4y+\cfrac{35y}{3} \right)=3(141)}\implies 12y+35y=423 \\\\\\ 47y=423\implies y=\cfrac{423}{47}\implies \blacktriangleright y = 9 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{5y}{3}}\implies x = \cfrac{5(9)}{3}\implies \blacktriangleright x = 15 \blacktriangleleft

4 0
4 years ago
A track has lanes 1 meter wide. The turn radius of the inner lane is 25 meters. To make a fair race, the starting line in each l
Angelina_Jolie [31]
Assuming that there are N lanes and runners are running in the middle of each lane, 
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))

you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.  
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane
8 0
3 years ago
1+h+j.h÷4; use h=8, and j=2​
horrorfan [7]

Answer:

1+8+2/4 = 9.5

Step-by-step explanation:

yeppp that's itttt

8 0
3 years ago
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