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2 years ago

5

I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would

appreciate it!

1 answer:

Fittoniya [83]2 years ago

5 0

Answer:

1436.01cm3

Step-by-step explanation:

A=4πr2 V=4 3πr3 Solving forV V=A3/2 6π=615.543/2 6·π≈1436.01254cm³

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The students on the right hand side had better overall results

There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.

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1 year ago

Dave buys a baseball catchers equipment for $295. The tax rate is 7.9%. How much tax did Dave pay? Round your answer to the near

Liono4ka [1.6K]

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2 years ago

Write a minor function for the line with the slope of -5 that passes through points (7,3)

Ilia_Sergeevich [38]

The equation of the line is $5x+y-38=0$

Step-by-step explanation:

The slope is $m=-5$

Also, the line passes through the points $(7,3)$

To find a line with slope $m=-5$ that passes through the points $(7,3)$ , let us use the equation of a line with slope that passes through the point is given by $(y-y_{1} )=m(x-x_{1} )$ where m is the slope and $(x_{1} ,y_{1} )$ are the points $(7,3)$ .

Thus, substituting the values in the equation of a line, we get,

$(y-3)=-5(x-7)$

Multiplying the term $(x-7)$ by -5, we get,

$y-3=-5 x+35$

Adding both sides by 5x,

$5x+y-3=35$

Subtracting 35 from both sides of the equation,

$5x+y-38=0$

Thus, the equation of the line is $5x+y-38=0$

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3 years ago

David's Parents have a sandwich shop. They sell sandwiches for $5 each and

Marianna [84]

Answer:

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8 0

2 years ago

Given: ABCD trapezoid, BK ⊥ AD , AB=DC AB=8, AK=4 Find: m∠A, m∠B

Elis [28]

Answer:

$m\angle B=m\angle C=120^{\circ}$

$m\angle A=m\angle D=60^{\circ}$

Step-by-step explanation:

Trapezoid ABCD is isosceles trapezoid, because AB = CD (given). In isosceles trapezoid, angles adjacent to the bases are congruent, then

$\angle A\cong \angle D;$
$\angle B\cong \angle C.$

Since BK ⊥ AD, the triangle ABK is right triangle. In this triangle, AB = 8, AK = 4. Note that the hypotenuse AB is twice the leg AK:

$AB=2AK.$

If in the right triangle the hypotenuse is twice the leg, then the angle opposite to this leg is 30°, so,

$m\angle ABK=30^{\circ}$

Since BK ⊥ AD, then BK ⊥ BC and

$m\angle KBC=90^{\circ}$

Thus,

$m\angle B=30^{\circ}+90^{\circ}=120^{\circ}\\ \\m\angle B=m\angle C=120^{\circ}$

Now,

$m\angle A=m\angle D=180^{\circ}-120^{\circ}=60^{\circ}$

7 0

2 years ago