7/30 pound of chicken. Since 7 is not divisible by 3, you will have to express 7/10 as 21/30 as 21 is divisible by 3.
21/30 divided by 3 people is 7/30
Thus each person gets 7/30 pounds of chicken
Answer:
216
Step-by-step explanation:
Total of octagon amount is 1080, so set it equal.
x + 2x + 3x + 4x + 6x + 7x + 8x + 9x = 1080
45x = 1080
/45 /45
x = 24
Then plug in for largest number.
9 (24) = 216
Answer:
O perímetro do outro triângulo deve ser ou de 30 unidades de comprimento, ou de 3.33 unidades de comprimento.
Step-by-step explanation:
Dois triângulos semelhantes possuem razão entre suas áreas igual a 9.
O perímetro tem grau um, enquanto a área tem grau 2. Isto implica que a razão entre os perímetros é a raiz quadrada da razão entre as áreas, então a razão entre os perímetros é de 3.
Se o perímetro de um deles é 10, o perímetro do outro deve ser:
Ou 10*3 = 30, ou 
O perímetro do outro triângulo deve ser ou de 30 unidades de comprimento, ou de 3.33 unidades de comprimento.
just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)
![\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%20in%20meters%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-4.9t%5E2%2Bv_ot%2Bh_o%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Ctextit%7Binitial%20velocity%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h_o%3D%5Ctextit%7Binitial%20height%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bof%20the%20object%7D%5C%5C%20h%3D%5Ctextit%7Bobject%27s%20height%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bat%20%22t%22%20seconds%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20h%28x%29%3D-5%28%5Cstackrel%7B%5Cmathbb%7BF~O~I~L%7D%7D%7Bx%5E2-8x%2B16%7D%29%2B180%5Cimplies%20h%28x%29%3D-5x%5E2%2B40x-80%2B180%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20h%28x%29%3D-5x%5E2%2B%5Cstackrel%7B%5Cstackrel%7Bv_o%7D%7B%5Cdownarrow%20%7D%7D%7B40%7D%20x%2B%5Cstackrel%7B%5Cstackrel%7Bh_o%7D%7B%5Cdownarrow%20%7D%7D%7B%5Cboxed%7B100%7D%7D~%5Chfill)
Answer:5,467
Step-by-step explanation:
since the decimal in under .2, it rounds down so rounding the number down to the nearest whole number would be 5467