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kykrilka [37]
3 years ago
14

Can you please answer the whole page I’ll give you all the points I have and Brainiest answer

Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0

QUESTION 1

The given circle has equation:

x^2+y^2=16

We can rewrite to obtain;

(x-0)^2+(y-0)^2=4^2

This is equation is now in the form;

(x-h)^2+(y-k)^2=r^2

Where (h,k)=(0,0) is the center of the circle and r=4 is the radius.

QUESTION 2

The center of the circle is at (1,1) and passes through the point (4,5).

The radius of this circle is given by;

r=\sqrt{(4-1)^2+(5-1)^2}

r=\sqrt{(3)^2+(4)^2}

r=\sqrt{9+16}

r=\sqrt{25}

r=5 units.

We substitute into the formula;

(x-h)^2+(y-k)^2=r^2

(x-1)^2+(y-1)^2=5^2

(x-1)^2+(y-1)^2=25

Expand if you wish;

x^2-2x+1+y^2-2y+1=25

x^2+y^2-2x-2y+2-25=0

x^2+y^2-2x-2y-23=0

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