Can I get help with 3 through 5

the outdoor temperature was 8 degrees at midnight. The temperature declined 5 degree during each of the next 3 hours What was th

kompoz [17]

I would say it was 3 degrees at 3am

4 0

3 years ago

A rectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. The equation (x + 5)x = 104

mina [271]

1. Regroup terms
x(x+5)=104

2. Expand
x^2+5x=104

3. Move all terms to one side
x^2+5x-104=0

4. Factor x^2+5x-104
(x-8)(x+13)=0

5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8

6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104

The dimensions are 13 and 8, have a nice day :D

8 0

3 years ago

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In a certain year, the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell

satela [25.4K]

Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

The equivalent multiplier for an increase of a% is given by: $\frac{100 + a}{100}$

The equivalent multiplier for an decrease of a% is given by: $\frac{100 - a}{100}$

In this problem:

The price at the beginning of January was of a.

Increase of 20% in January, hence $1.2a$ .

Decrease of 20% in February, hence $1.2(0.8)a$ .

Increase of 25% in March, hence $1.2(0.8)(1.25)a$ .

Decrease of x% in April, hence $1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a$

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

$a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a$

$1.2\left(\frac{100 - x}{100}\right) = 1$

$\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}$

$\frac{100 - x}{100} = 0.8333$

$100 - x = 83.33$

$x = 16.67$

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

6 0

2 years ago

2 1 point

mafiozo [28]

Answer:

The graph has a minimum.
The graph has a y-intercept at (0, -3).
The solutions ... are -1 and 3.
The vertex is located at (1, -4).
In the equation, 'a' would be positive.

Step-by-step explanation:

When the graph has a low point, it has a minimum. 'a' is positive in that case. The coordinates of that low point are (1, -4). That point is the vertex.

The graph crosses the y-axis at y = -3, so the y-intercept is (0, -3).

The graph crosses the x-axis at (-1, 0) and (3, 0). These points represent the solution to the equation y = 0.

The graph has a minimum.
The graph has a y-intercept at (0, -3).
The solutions ... are -1 and 3.
The vertex is located at (1, -4).
In the equation, 'a' would be positive.

5 0

3 years ago

What is the value of h when the function is converted to vertex form?

Rudik [331]

The Vertex Form is $y=(x+5)^2+10$
So $h=5$

Hope this helps!!

7 0

3 years ago

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