Answer:
The points that fits the equation would be option D.
X - (9x - 10) + 11 = 12x + 3(-2x +

) equals
x = 
.
First, simplify brackets. / Your problem should look like: x - 9x + 10 + 11 = 12x + 3(-2x +

).
Second, simplify x - 9x + 10 + 11 to -8x + 10 + 11. / Your problem should look like: -8x + 10 + 11 = 12x + 3(-2x +

).
Third, simplify -8x + 10 + 11 to -8x + 21. / Your problem should look like: -8x + 21 = 12x + 3(-2x +

).
Fourth, expand. / Your problem should look like: -8x + 21 = 12x - 6x + 1.
Fifth, simplify 12x - 6x + 1 to 6x + 1./ Your problem should look like: -8x + 21 = 6x + 1.
Sixth, add 8x to both sides. / Your problem should look like: 21 = 6x + 1 + 8x.
Seventh, simplify 6x + 1 + 8x to 14x + 1. / Your problem should look like: 21 = 14x + 1.
Eighth, subtract 1 from both sides. / Your problem should look like: 21 - 1 = 14x.
Ninth, simplify 21 - 1 to 20. / Your problem should look like: 20 = 14x.
Tenth, divide both sides by 14. / Your problem should look like:

= x.
Eleventh, simplify

to

. / Your problem should look like:

= x.
Twelfth, switch sides. / Your problem should look like: x =

which is your answer.
Answer:
$408.25
Step-by-step explanation:
9.50 times 40=380
9.50 times 1.5= 14.25
14.25 times 2=28.50
380+28.50=
$408.25
<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.