Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α = /r
=2.513/0.287
=8.756 rad/s²
Answer:
The answer is D.
Explanation:
There are 12 atoms of H present in ammonium phosphate (NH4)3PO4.
Answer:
a)a=5.01m/s^2
b)t=11.26s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X(2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve
to solve the question a, we can use the ecuation number 2
Vo=0
Vf=10.5 m/s
x=11m
{Vf^{2}-Vo^2}/{2.a} =X
{Vf^{2}-Vo^2}/{2.x} =a
{10.5^{2}-0^2}/{2x11} =a
a=5.01m/s^2
to find the time we can use the ecuation number 1
Vf=Vo+a.t
t=(Vf-Vo)/a
t=(10.5-0)/5.01=2.09s
part b
in this case the spees is constant, so the movement is defined by the following ecuation
X=VT
t=x/v
t=96.3/10.5=9.17s
to find the total time we sum the times when the speed is constant and when the acceleration is constan
t=9.17+2.09
t=11.26s
Answer:
fr = 65.46 N
, a = 8.74 m / s² and vf = 19.25 m / s
Explanation:
We write a reference system with an axis parallel to the slide and gold perpendicular axis, in this system we decompose the weight
sin 21.2 = Wx / W
cos21.2 = Wy / W
Wx = W sin21.2
Wy = W cos 21.2
We form Newton's equations
X axis
Wx -fr = m a
Y Axis
N- Wy = 0
N = Wy
fr = μ N
fr = μ (W cos 21.2)
fr = 0.113 63.4 9.8 cos 21.2
fr = 65.46 N
We replace and calculate the acceleration
W sin 21.2 - μ W cos 21.2 = m a
a = g (sin21.2 - μ cos 21.2)
a = 9.8 (without 21.2 - 0.113 cos 21.2)
a = 8.74 m / s²
This acceleration is along the slope of the slide, so we can calculate the distance
d = 21.2 m
vf² = v₀² + 2 a d
vf² = 0 + 2 a d
vf = √(2 8.74 21.2)
vf = √ (370,576)
vf = 19.25 m / s
The partial pressure of the O2 is 36.3 kiloPascal when the air pressure in the mask is 110 kiloPascal based on the isotherm relation. This problem can be solved by using the isotherm relation equation which stated as Vx/Vtot = px/ptot, where V represents volume, p represents the pressure, x represents the partial gas, and tot represents the total gas<span>. Calculation: 33/100 = px/110 --> px = 36.3</span>
