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3 years ago

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A 0.40 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frict

ionless surface. The object is released from rest when the spring is compressed 0.17 m.
(a) Find the force on the object.
(b) Find its acceleration at that instant.

1 answer:

nirvana33 [79]3 years ago

8 0

Answer:

Part a)

$F = 26.7 N$

Part b)

$a = 66.7 m/s^2$

Explanation:

Part a)

Force on the object due to spring force is given as

$F = kx$

here we know that

$k = 157 N/m$

$x = 0.17 m$

so we have

$F = 157\times 0.17$

$F = 26.7 N$

Part b)

Acceleration of the object is given as

$a = \frac{F}{m}$

$a = \frac{26.7}{0.40}$

$a = 66.7 m/s^2$

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Someone help please by providing work and answers please :)

ohaa [14]

Mass is a property of the object. It doesn't depend on anything else,
and it doesn't change when the object goes to different places.
Its mass is always the same.

If it's 20,000 kilograms on Earth, then it's 20,000 kilograms on the
Moon, on Mars, in school, in bed, in love, in trouble, in water,
on Pluto, on Halley's comet, or in free fall in outer space.

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Now, if the question was talking about WEIGHT, then we would have
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VLD [36.1K]

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