Ask question

Ask question

All categories

3 years ago

14

A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency o

f 2 Hz, what is the speed of the wave that travels through the string to the other end?

1 answer:

GrogVix [38]3 years ago

4 0

Wave speed = (wavelength) x (frequency)

Wave speed = (0.5 m) x (2 /sec)

<em>Wave speed = 1 m/s</em>

You might be interested in

True or false energy is always lost in a circuit

Llana [10]

Explanation:

Electrons will gain energy as they are "pushed" from different points in the circuit. This energy is then lost when the electrons flow through circuit components such as a light bulb.

7 0

2 years ago

What is the speed of a bobsled who's distance-time graph indicates that it traveled 106m in 26s?

swat32

To find the speed of the bobsled, you divide the distance by time. So, when you divide 106 by 26, you get 4.07. This means the speed of the bobsled is about 4 miles per hour.

3 0

2 years ago

Why does the Moon seem to change shape?

Licemer1 [7]

Answer:

A

Explanation:

3 0

2 years ago

Read 2 more answers

A spring-loaded toy gun is used to shoot a ball of mass 1.5 kg straight up in the air, as shown. The spring has spring constant

asambeis [7]

Answer:

Part a)

U = 15.5 J

Part b)

h = 1.05 m

Part c)

v = 4.55 m/s

Explanation:

Part a)

Initial potential energy stored in the spring is given by

$U = \frac{1}{2}kx^2$

now we have

$k = 777 N/m$

x = 20.0 cm

now from above formula we will have

$U = \frac{1}{2}(777)(0.20)^2$

$U = 15.5 J$

Part b)

By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position

$\frac{1}{2}kx^2 = mgh$

$15.5 = 1.5(9.8)h$

$h = 1.05 m$

So maximum height from gun is 1.05 m

Part c)

For muzzle velocity of the ball we can use the energy conservation again

According to which the final kinetic energy of the ball = initial spring energy stored in it

$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$

$(\frac{1}{2})(1.5 v^2) = 15.5$

$v = v = 4.55 m/s$

4 0

2 years ago

what is the speed of a boy moving around a circular park of radius 6m if he goes around the park in 20s

seropon [69]

Answer:

1.884 meters per second

Explanation:

s = d/t

d = C = 2πr = 2π(6) = 37.68 m

t = 20 s

s = (37.68 m)/(20 s)

s = 1.884 m/s

7 0

2 years ago

Read 2 more answers