Answer : The mass of required is 71.175 grams.
Explanation :
To calculate the moles of nitrogen gas, we use the equation given by ideal gas :
PV = nRT
where,
P = Pressure of nitrogen gas = 763 torr
V = Volume of the nitrogen gas = 40.0 L
n = number of moles of gas = ?
R = Gas constant =
T = Temperature of helium gas =
Putting values in above equation, we get:
Now we have to calculate the moles of .
The balanced chemical reaction is:
From the balanced chemical reaction, we conclude that
As, 3 moles of produced from 2 moles
So, 1.642 moles of produced from
moles
Now we have to calculate the mass of .
Molar mass of = 65 g/mol
Therefore, the mass of required is 71.175 grams.