The growth is decaying, the original value is 500 and the common multiplier is 5, 500 divided by 5 turns to 100. 100/5=20. 20/5=4. x/5 or 1/5 if it has to be in a fraction format
Answer:
t
Step-by-step explanation:
t divided by 8 negative 9
Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer:
Simplifying the expression: we get
Step-by-step explanation:
We need to simplify the expression:
First we will solve terms inside the bracket
Converting mixed fraction into improper fraction, we get:
Replacing the term:
Now, taking LCM of: 5,3,4,2 we get 60
Now multiply 60 with each term inside the bracket
Now, combine like terms
Now, multiply all terms with 2
So, Simplifying the expression: we get
Answer:
We can only infer that OA=OB=PD=DE.
Step-by-step explanation:
Since, if two circles are congruent then their radius must be equal.
And, here A and B are the points in the circumference of circle O therefore, the distance of these points from the center O of the circle is the radius of the circle.
So, OA=OB. ( if we join the points O and C then OA=OB=OC)
Similarly, In Circle P, PE= PD. ( if we join the points P and CF then PD=PE=PF).
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Credits to: parmesanchilliwack