It would be 100.60 because we're adding like to the atmosphere it connects to lubricator and then it turns so that's 100.60
The energy transferred is 28.5 j
<em><u>calculation</u></em>
energy is calculate MCΔT formula where,
M(mass)= 6.30 grams
C(specific heat capacity)= 0.377 j/g
ΔT(change in temperature)= 32.0c- 20 c= 12 c
Energy is therefore= 6.30 g x 0.377 j/g /c x 12 c =<u>28.5 j</u>
Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,
Where, m is mass of iron
s is specific heat of iron
d T is change in temperature in celcius
If
1 cal = 4.2 J
Then,
Thus 0.389 k cal of enrgy is required by a 15.6 g Fe to reach to 355 C^0
The electrons will move more rapidly resulting in a higher pressure even at a consistent volume
According to Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺).
1) NH₄⁺(aq) + H₂O(l) ⇄ NH₃ + H₃O⁺(aq); the ammonium cation (NH₄⁺) gives proton to water.
2) [Co(H₂O)₆]³⁺ + H₂O ⇌ [Co(H₂O)₅(OH)]²⁺ + H₃O⁺; cobalt cation (Co³⁺) forms complex cation with six molecules of water, which act like acid and gives protons.
3) CH₂NH₃⁺(aq) + H₂O(l) ⇄ CH₂NH₂ + H₃O⁺(aq); H⁺ is cationic form of atomic hydrogen, the hydrated form of the hydrogen cation is the hydronium ion H₃O⁺(aq).
