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UNO [17]
3 years ago
9

The by-product of the chlorination of an alkane is​

Chemistry
1 answer:
Elanso [62]3 years ago
7 0

The by-product of the chlorination of an alkane is​  <u>HCl</u>

Explanation:

  • Chlorination is the process of adding chlorine to drinking water to disinfect it and kill germs. Different processes can be used to achieve safe levels of chlorine in drinking water.
  • Chlorination of alkane gives a mixture of different products.
  • When consider mechanism of alkanes chlorination, free radicals are formed during the reaction to keep the continuous reaction.
  • Different alkyl chloride compounds, extended carbon chains compounds and HCl are formed as products in product mixture.
  • Chlorination byproducts, their toxicodynamics and removal from drinking water.
  • Halogenated trihalomethanes (THMs) and haloacetic acids (HAAs) are two major classes of disinfection byproducts (DBPs) commonly found in waters disinfected with chlorine
  • Chlorine is available as compressed elemental gas, sodium hypochlorite solution (NaOCl) or solid calcium hypochlorite (Ca(OCl)2
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blagie [28]

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C?

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Which area is most likely closest to a salt marsh or an estuary?
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Answer:

coastal area with very high tides deep ocean water miles from a river's mouth

Explanation:

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4 0
2 years ago
Which of the following is a unit of volume in the English system of measurement? A. Meters B. Gallons C.liters per cubic gram D.
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8 0
3 years ago
Read 2 more answers
Ibuprofen is a drug used to manage mild pain, fever, and inflammation. It is a chiral drug, and only the S enantiomer, whose spe
madam [21]

Answer:

Specific Rotation = 105º

S% in mixture = 92%

Explanation:

Specific rotation in organic compounds varies linearly, then the enantiomeric excess can be express as:

e.e. = \frac{\alpha }{\alpha pure}

Where alpha is the specific rotation of the mixture and alpha pure is the specific rotation of the excess enantiomer.

Then, knowing that the S enantiomer is in excess you can calculate the specific rotation of that mixture:

84=\frac{\alpha }{125.0}*100

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For calculating the percentage of S you should remember that the enantiometric excess is the percentage of excess of a certain enantiomer, for example in this case:

84 = S-R

Since S is in Excess

Also, it is true:

100=S+R

Then you can solve the system of linear equations, finding:

8=R\\92=S

Hope it helps!

4 0
3 years ago
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