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Archy [21]
2 years ago
6

(worth 15 points) please help, i’ll give brainliest

Mathematics
1 answer:
seraphim [82]2 years ago
3 0

Answer:

B

Step-by-step explanation:

You might be interested in
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
Divide 12x^4+17^3+8x-40 by x-2
chubhunter [2.5K]

Answer:

12x^3 + 24x^2 + 48x + 104 + (5081/x-2)

Step-by-step explanation:

12x^4 + 17* (17*17) + 8x -40/ x-2

1. remove the parenthesis

12x^4 + !7 * 17 * 17 + 8x -40 / x-2

2. multiply 17 by 17

12x^4 + 289 * 17 + 8x -= 40 /x-2

3. multiply 289 by 17

12x^ = 4913 + 8x - 40 / x-2

4. move 4913

12x^4 + 8x + 4913 - 40 / x-2

5. subtract 40 from 4913

12x^4 + 8x + 4873 / x-2

6. set up polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0

x-2 into 12x^4 + 0x^3 + 0x^2 + 8x + 4873

7. divide the highest order term  in the dividend 12x^4 by the highest order term in divisor x = 12x^3

8. multiply by new quotient term

12x^3 * x-2 = 12x^4 -24x^3

9. the expression needs to be subtracted from the dividend, so change all the signs in 12x^4 - 24x^3

12x^4 + 0x^3 - 12x^4 + 24x^3

10. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+24x^3

11.  pull the next term from the original dividend down into the current dividend

+24x^3 + 0x^2

12.  divide the highest order term in the dividend 24x^3 by the highest order term in divisor x = 24x^2

12x^3 + 24x^2

13. multiply new quotient by the divisor

24x^3 * x-2 = 24x^3 - 48x^2

14. the expression needs to be subtracted from the dividend, so change all the signs in 24x^3 - 48x^2

24x^3 + 0x^2 - 24x^3 + 48x^2

15. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+48x^2

16. pull the next terms from the original dividend down to the current dividend

+ 48x^2 + 8x

17. divide the highest order term in the dividend 48x^2 by the highest order term in the divisor = 48x

12x^3 + 24x^2 + 48x

18. multiply the new quotient term by the divisor

48x * x - 2 = 48x^2 - 96x

19. the expression needs to be subtracted from the dividend, so change all the signs in 48x^2 - 96x

-48x^2 + 96x

20. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

48x^2 + 8x - 48x^2 + 96x

= 104x

21. pull the next terms from the original dividend down to the current dividend

+ 104x + 4873

22. divide the highest order term in the dividend 104x by the highest order term in the divisor x = 104

23. divide the new quotient by the divisor

104 * x -2 = 104x - 208

24. the expression needs to be subtracted from the dividend, so change all the signs in 104x - 208

104x + 4873 - 104x + 208 = 5081

25. the final answer is the quotient plus the remainder over the divisor

12x^3 + 24x^2 + 48x + 104 + (5081 / x - 2)

5 0
3 years ago
How do you write this as an equation. Pls help<br><br> A number multiplied by 2/5 is 3/20<br> .
Naddika [18.5K]

Answer:

2/5x = 3/20 or 2/5 *x = 3/20

Step-by-step explanation:

These are the same thing just different ways to write. The x represents the unknown number

5 0
3 years ago
Explain why the function is discontinuous at the given number
Novosadov [1.4K]

Answer:

  left limit = 2 ≠ 1/2 = right limit

Step-by-step explanation:

A function is discontinuous if the limit of the function value approaching the point from the left is different than the limit approaching from the right.

Here, the left limit is 2 and the right limit is 1/2. The limits are different, which is why the function is discontinuous at x=-1.

7 0
3 years ago
Please please help me. i’ll literally send you money. i need to pass please help
mihalych1998 [28]
<h3>Answer: Approximately 6.4 units</h3>

==================================================

Explanation:

The origin is the point (0,0)

Use the distance formula to find the distance from (0, 0) to (4, -5)

Let

(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\

be our two points. Plug those values into the distance formula below and use a calculator to compute

d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\

The distance between the two points (0,0) and (4,-5) is approximately 6.4 units.

6 0
3 years ago
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