To make the motor turn faster we can:
(a) increase the current
(b) use stronger magnets
(c) push the magnets closer to the coil
(d) put an iron centre piece into the coil
(e) adding more sets of coils
Answer:
Explanation:
Given
Velocity of jet relative to the carrier
Velocity of jet carrier to the wind
Velocity of wind
Length of runway=126 m
thus =20.11+8.94=29.05
=29.05+45=74.05 m/s
to find acceleration
here u=0,v=74.05 m/s
case -2
Velocity of jet relative to the carrier
Velocity of jet carrier to the wind
Velocity of wind
Length of runway=126 m
here u=0,v=77.7 m/s
First there are many ways to approach this problem. The simplest and most direct in my opinion is this approach:
vf^2=v1^2+2ad
so when the height reaches a maximum of 35m the velocity is zero for a split second before starting to fall. So we set vf=0 and solve for v1.
v1=sqrt(2gd)=sqrt(2*9.8*35)= 26.2m/s
for initial velocity needed to reach 35m height.
Any questions please ask!
Gravity and falling objects