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elena-s [515]
3 years ago
9

Explain in details the concept of economic geography​

Physics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

In the words of Hartshorn and Alexander: “Economic Geography is the study of the spatial variation on the earth’s surface of activities related to producing, exchanging and consuming goods and services. Whenever possible the goal is to develop generalizations and theories to account for these spatial variations.”

Explanation:

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How does the north pole of a magnet respond to the poles of other magnets?
tensa zangetsu [6.8K]

Answer:

Explanation:

A magnet has a magnetic field around it which originates at the north pole and enters through the south pole.

In a magnet, like poles will repel each other and unlike poles will attract.

  • The north pole of one magnet will repel another north pole of another magnet.
  • North pole of one magnet will attract the south pole of another magnet.
  • This is the law of attraction and repulsion of magnet.
8 0
3 years ago
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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo
BARSIC [14]

We are given that,

\frac{dx}{dt} = 4ft/s

We need to find \frac{d\theta}{dt} when x=8ft

The equation that relates x and \theta can be written as,

\frac{x}{6} tan\theta

x = 6tan\theta

Differentiating each side with respect to t, we get,

\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}

\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}

\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}

Replacing the value of the velocity

\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2

\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta

The value of cos \theta could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

cos\theta = \frac{6}{10}

\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2

\frac{d\theta}{dt} = \frac{24}{25}

Search light is rotating at a rate of 0.96rad/s

4 0
2 years ago
If a plane is flying level at 910 km/h and the banking angle is not to exceed 50 ∘, what's the minimum curvature radius for the
hoa [83]

Answer:

5.5 km

Explanation:

First, we convert the distance from km/h to m/s

910 * 1000/3600

= 252.78 m/s

Now, we use the formula v²/r = gtanθ to get our needed radius

making r the subject of the formula, we have

r = v²/gtanθ, where

r = radius of curvature needed

g = acceleration due to gravity

θ = angle of banking

r = 252.78² / (9.8 * tan 50)

r = 63897.73 / (9.8 * 1.19)

r = 63897.73 / 11.662

r = 5479 m or 5.5 km

Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km

4 0
3 years ago
What do we call the movement of electric charge?<br> A. Power B. Voltage C. Resistance D. Current
Alex Ar [27]
D. Current

Hope I helped!
4 0
2 years ago
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Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B
tatyana61 [14]

\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

3 0
2 years ago
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