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4 years ago

If you were a pastor, and you were getting married, would you hire a pastor, or would you do the wedding yourself?

Physics

2 answers:

bearhunter [10]4 years ago

4 0

I would hire a pastor.

ki77a [65]4 years ago

3 0

In this kind of question, it would be someone's opinion. In my opinion, I think I would hire a paster because it would be awkward. Do you agree?

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A portion of the atmosphere that becomes warmer than surrounding air will ____.

earnstyle [38]

A portion of the atmosphere that becomes warmer than surrounding air will expand and rise. The warmer atmosphere the more space between the molecules. Therefore, warmer atmosphere expands to allow more space for the molecules. Cool air on the other hand, contracts because the molecules in cool air need less space.

3 0

3 years ago

An open container holds ice of mass 0.555 kg at a temperature of -16.6 ∘C . The mass of the container can be ignored. Heat is su

s2008m [1.1K]

Answer: A. 23.59 minutes.

B. 249.65 minutes

Explanation: This question involves the concept of Latent Heat and specific heat capacities of water in solid phase.

Latent heat of fusion is the total amount of heat rejected from the unit mass of water at 0 degree Celsius to convert completely into ice of 0 degree Celsius (and the heat required for vice-versa process).

Specific heat capacity of a substance is the amount of heat required by the unit mass of a substance to raise its temperature by 1 kelvin.

Here, given that:

mass of ice, m= 0.555 kg

temperature of ice, T= -16.6°C

rate of heat transfer, $q=820 J.min^{-1}$

specific heat of ice, $c_{i}= 2100 J.kg^{-1}.K^{-1}$

latent heat of fusion of ice, $L_{i}=334\times10^{3}J.kg^{-1}$

Asked:

1. Time require for the ice to start melting.

2. Time required to raise the temperature above freezing point.

Sol.: 1.

We have the formula:

$Q=mc\Delta T$

Using above equation we find the total heat required to bring the ice from -16.6°C to 0°C.

$Q= 0.555\times2100\times16.6$

$Q= 19347.3 J$

Now, we require 19347.3 joules of heat to bring the ice to 0°C and then on further addition of heat it starts melting.

∴The time required before the ice starts to melt is the time required to bring the ice to 0°C.

$t=\frac{Q}{q}$

$=\frac{19347.3}{820}$

= 23.59 minutes.

Sol.: 2.

Next we need to find the time it takes before the temperature rises above freezing from the time when heating begins.

Now comes the concept of Latent heat into the play, the temperature does not starts rising for the ice as soon as it reaches at 0°C it takes significant amount of time to raise the temperature because the heat energy is being used to convert the phase of the water molecules from solid to liquid.

From the above solution we have concluded that 23.59 minutes is required for the given ice to come to 0°C, now we need some extra amount of energy to convert this ice to liquid water of 0°C.

We have the equation: latent heat, $Q_{L}= mL_{i}$

$Q_{L}= 0.555\times334\times10^{3}= 185370 J$

Now the time required for supply of 185370 J:

$t=\frac{Q_{L}}{q}$

$t=\frac{185370}{820}$

t= 226.06 minutes

∴ The time it takes before the temperature rises above freezing from the time when heating begins= 226.06 + 23.59

= 249.65 minutes

8 0

3 years ago

Which factors allow for life on Earth

Elan Coil [88]

Are there supposed to be multiple choices for this question?

6 0

4 years ago

Read 2 more answers

An air-track cart is attached to a spring and completes one oscillation every 5.67 s in simple harmonic motion. at time t = 0.00

Masteriza [31]

The cart is moving by simple harmonic motion, and its position at time t is described by
$x(t) = A \cos (\omega t)$
where
A is the amplitude of the oscillation
$\omega$ is the angular frequency

The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released:
A=0.250 m

The period of the motion is T=5.67 s, and the angular frequency is related to the period by
$\omega = \frac{2 \pi}{T}= \frac{2 \pi}{5.67 s} =1.11 rad/s$

Therefore now we can calculate the position of the system at the time t=29.6 s:
$x(29.6 s)=(0.250 m)\cos ((1.11 rad/s)(29.6 s))=+0.033 m$

3 0

3 years ago

Read 2 more answers

In addition to displacement, which of the following must be used for a more complete description of the average velocity of an o

Anastasy [175]

Change in time is also needed

8 0

3 years ago