Answer:
Step-by-step explanation:
Answer:
135.5ft
Step-by-step explanation:
THIS COMPLETE THE QUESTION
flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.
Let X be the length of the wire
Let y be the height of the pole
X= Y + 14
Y= X -14
We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)
Using Pythagoras theorem
X²= 60² + Y²
X² = 3600 + Y²
if we subsitute for Y we have
X² = 3600 + (X -14)²
X² = 3600 +X² -14X-14X+196
X²-X²+ 28X= 3600+196
28X= 3796
X= 3796/28
=135.5ft
hence length of the wire is 135.5ft
Answer: s > 5
Step-by-step explanation:
-s² + 25s - 100 > 0
Coefficient of s² is -1, multiply the equation through by -1.
-1 × (-s² + 25s - 100)
s² — 25s + 100
ax² + bx + c
Then you get the factors x and y that gives x + y = b and xy = c
b = -25 and c = 100, x = -20 and y = -5
-20 × -5 = 100 and -20 + -5 = -25
Then
s² — 20s — 5s + 100 > 0
Factorising,
s (s — 20) — 5(s — 20) > 0
(s — 5)(s — 20) > 0
(s — 5) > 0 and (s — 20) > 0
s>5 and s>20
s > 5
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