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4 years ago

The exact answer and the estimated answer will always be the same. true or false

Mathematics

2 answers:

RideAnS [48]4 years ago

7 0

It might be the right answer but it is not always, so false

lisov135 [29]4 years ago

4 0

The above statement is false

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Can't anybody help me with this ik math sucks but help

Agata [3.3K]

Answer:

Step-by-step explanation:

6 0

3 years ago

27 x 9 ^3x can be written in the form 3^k Find out what k is an expression in term of x

amid [387]

k = 3 + 6x

note that 27 = 3³ and 9 = 3²

27 × $9^{3x}$ = 3³ × (3²)^3x = 3³ × $3^{6x}$ = $3^{3 + 6x}$

hence k = 3 + 6x

4 0

3 years ago

Read 2 more answers

the roof of a house rises vertically 2 feet for ever 12 feet of horizontal distance. What is the slope, or pitch of the roof?

makvit [3.9K]

Answer:

$slope=\frac{1}{6}$

Step-by-step explanation:

Slope is the fraction, or ratio, of the vertical change over the horizontal change of two sets of data. In this case, the slope is the rate at which the house rises over expands:

$slope=\frac{vertical}{horizontal}=\frac{2}{12}=\frac{1}{6}$

Simplifying the fraction to simplest form gives an overall rate of 1/6 ft.

5 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

Austin started a new job working 4 hours every 2 weeks.

adelina 88 [10]

Answer:

this app is not helpful get off

Step-by-step explanation:

you will not be smart if u cheat LOL

7 0

3 years ago