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OLEGan [10]
3 years ago
12

Jordy tried to prove that △ A B E ≅ △ B C D △ABE≅△BCDtriangle, A, B, E, \cong, triangle, B, C, D. A A B B C C D D E E Statement

Reason 1 ∠ B C D ≅ ∠ A B E ∠BCD≅∠ABEangle, B, C, D, \cong, angle, A, B, E Given 2 ∠ C D B ≅ ∠ B E A ∠CDB≅∠BEAangle, C, D, B, \cong, angle, B, E, A Given 3 B D ↔ ∥ A E ↔ BD ∥ AE B, D, with, \overleftrightarrow, on top, \parallel, A, E, with, \overleftrightarrow, on top Given 4 ∠ C B D ≅ ∠ B A E ∠CBD≅∠BAEangle, C, B, D, \cong, angle, B, A, E Corresponding angles on parallel lines are congruent. 5 △ A B E ≅ △ B C D △ABE≅△BCDtriangle, A, B, E, \cong, triangle, B, C, D Angle-angle-angle congruence What is the first error Jordy made in his proof? Choose 1 answer: Choose 1 answer: (Choice A) A Jordy used an invalid reason to justify the congruence of a pair of sides or angles. (Choice B) B Jordy only established some of the necessary conditions for a congruence criterion. (Choice C) C Jordy established all necessary conditions, but then used an inappropriate congruence criterion. (Choice D) D Jordy used a criterion that does not guarantee congruence.
Mathematics
2 answers:
Sonja [21]3 years ago
8 0

Answer:

yes it is A and C

Step-by-step explanation:

Arte-miy333 [17]3 years ago
4 0

Answer:

what's the answer

ok

tell

me

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Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

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For the given function, there is no horizontal asymptote.

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(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

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