All categories

3 years ago

Plz help me evaluate this expression :

Mathematics

1 answer:

snow_tiger [21]3 years ago

6 0

The answer is C. (2jk)^-2

You might be interested in

Helppp!

lilavasa [31]

Answer:

It's the the 4th one. 6.3.3

5 0

2 years ago

(x+2)(4+y)(5+6)(2+x)(4+0.5x)

Yuki888 [10]

(x+2)(4+y)(5+6)(2+x)(4+0.5x)

combine like terms

(x+2) (4+y) (11) (x+2) (4+.5x)

11(x+2)^2 (4+y)(4+.5x)

distribute

11(x^2 +4x+2) (16+4y+2x+.5xy)

(11x^2+44x+22)(16+4y+2x+.5xy)

5.5 x^3 y + 22 x^3 + 66 x^2 y + 264 x^2 + 198 x y + 792 x + 176 y + 704

3 0

3 years ago

a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di

Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

$\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}$

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

$\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}$

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

$\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}$

Thus, the total prototypes will cost around $60.75

7 0

1 year ago

What is the direct variation equation if y varies directly with x and y = -12 when x = 6?

Reika [66]

It would be A because -2 times +6 equals -12

4 0

3 years ago

Find the force it would take to accelerate an 800-kg car at a rate of 5 m/s^2.

Mars2501 [29]

800/5 which is 160!!!!!!!!

5 0

3 years ago