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Rus_ich [418]
2 years ago
11

30 POINTS!!! Which choice is equivalent to the fraction below when x is greater than or equal to 3?

Mathematics
2 answers:
Bond [772]2 years ago
6 0

Answer:

the answer would be c

Step-by-step explanation:

like the hint says, rationalize the denominator by multiplying the numerator and denominator by the conjugate

(\sqrt{x} + \sqrt{x-3}), and then simplify after that...hope this helps :)

Mashcka [7]2 years ago
4 0

Answer: C.

\frac{9}{\sqrt{x} -\sqrt{x-3} }=\frac{9(\sqrt{x} +\sqrt{x-3} )}{x-(x-3)}=\frac{9(\sqrt{x} +\sqrt{x-3} )}{3}=3(\sqrt{x} +\sqrt{x-3})

Step-by-step explanation:

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Using principle of mathematical induction prove that 6^-1 divisble by 5 .​
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I suppose the claim is 5 \mid 6^n - 1 for n\in\Bbb N.

When n=1, we have 6^1 - 1 = 6 - 1 = 5, and of course 5 divides 5.

Assume the claim holds for n=k, that 5 \mid 6^k - 1. We want to use this to show it holds for n=k+1, that 5 \mid 6^{k+1} - 1.

We have

6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5

Since 5 \mid 6^k - 1, we can write 6^k - 1 = 5\ell for some integer \ell. Then

6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)

which is clearly divisible by 5. QED

5 0
1 year ago
Factor this polynomial completely.
Vladimir79 [104]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
A certain car can travel on a highway for 350 miles on 15 gallons of gas and in a city for 280 miles on 18 gallons of gas. If th
user100 [1]

Answer:

The car's average 18 number of miles per gallon

Step-by-step explanation:

The car has different efficiencies depending if its used on highway or city streets.

The efficiency on a highway is:

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The efficiency for city driving is:

E_c=\dfrac{280}{18}\;\text{miles/gal}=15.56\;\text{miles/gal}

We now that the car uses twice as many gallons for city driving as for highway driving. This means that, for every gallon consumed, 2/3 are for city driving and 1/3 are for highway driving.

Then, we can calculate how many miles makes the car on average as:

E=\dfrac{1}{3}E_h+\dfrac{2}{3}E_c\\\\\\E=\dfrac{1}{3}\cdot 23.33+\dfrac{2}{3}\cdot15.56=7.78+10.37=18.15\;\text{miles/gal}

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First you normalize 3x+4y=12 into y = -3/4 x + 3 (dividing by 4).

Then you observe that the slope of the line is -3/4 (it's always the factor with the x). A perpendicular line has the reciprocal slope. Reciprocal means inverted and negated. So -3/4 becomes +4/3.

The equation will thus look like y = 4/3 x + b. To find b, we fill in the given x intercept (0,2), (we get 2 = 4/3 * 0 + b). With x=0, b must be 2.

So the equation is: y = 4/3 x + 2

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