Question

30 POINTS!!! Which choice is equivalent to the fraction below when x is greater than or equal to 3?

Answer 1

Answer:

the answer would be c

Step-by-step explanation:

like the hint says, rationalize the denominator by multiplying the numerator and denominator by the conjugate

($\sqrt{x} + \sqrt{x-3}$), and then simplify after that...hope this helps :)

Answer 2

Answer: C.

$\frac{9}{\sqrt{x} -\sqrt{x-3} }=\frac{9(\sqrt{x} +\sqrt{x-3} )}{x-(x-3)}=\frac{9(\sqrt{x} +\sqrt{x-3} )}{3}=3(\sqrt{x} +\sqrt{x-3})$

Step-by-step explanation: