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suter [353]
3 years ago
8

Help pls

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer:

Check pdf

Step-by-step explanation:

Download pdf
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What is the area of the blue shaded region​???????
Anna [14]

Answer:

Step-by-step explanation:

22/7x7^2=154

22/7x3^2=28(approx)

154-28=126

5 0
3 years ago
Find the sum of even numbers from 34 to 234 inclusive
valentinak56 [21]
We have 

AP = 34,36,38......,234

a, (first term) = 34

n ( total terms ) =?

d ( common difference ) = 2

so, a +(n-1)d =an

34+(n-1)*2 = 234

(n-1)2 = 234-34

n-1 = 200/2

n = 100+1

n =101

Now sum of the even no.

Sn = n/2( 2a+9n-1)d)
       
       = 101/2 (2*34 +100*2)
 
        = 101/2 * 268
 
          =101 *134
 
         = 13534
7 0
3 years ago
When the polynomial is written in standard form, what are the values of the leading coefficient and the constant 5x + 2 - 3x^2
Arte-miy333 [17]

\bf 5x+2-3x^2\implies \stackrel{\boxed{\textit{standard form}}}{\underset{~\hfill \textit{constant}}{\stackrel{\textit{leading coefficient}}{\stackrel{\downarrow }{-3}x+5x+\underset{\uparrow }{2}}}}

3 0
3 years ago
3/4 5/6 16/25 9/15 smallest to largest
nydimaria [60]

Answer:

All you need to do is find a common denomianatorand then solve from least to greatest hope this helps!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A car had a value of $10,000 and depreciates at a rate of 7% a year. What is the cars value after 3 years.​
SOVA2 [1]

Answer:

Step-by-step explanation:

The exponential decay function is

v(t)=a(b)^t where a is the initial value of the car, b is the rate of decay, and t is the time in years. Our rate of decay can also be written as (1 - r) where r is the depreciation in decimal form. Our equation looks like this:

v(t)=10000(1-.07)^t which simplifies to

v(t)=10000(.93)^t Now we can solve our problem for any number of years you'd like. We've been tasked to find the value of the car after 3 years, so:

v(t)=10000(.93)^3 which simplifies a bit to:

v(t)=10000(.804357) so

v(t) = 8043.57

3 0
3 years ago
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