The confidence interval for the proportion of students attending a football game is [0.6592, 0.7044].
Confidence interval can be calculated by below formula

where the left part is the lower interval and right side is the higher interval.
Pcap = 750/1100
Pcap = 0.6818
Again to calculate
, as we know that the level of confidence is 90 percent so its value will be 1.645
now putting the values on the both side we can get ,
0.6818 - 1.645 x 0.014 < p < 0.6818 + 1.645 x 0.014
0.6818 - 0.023 < p < 0.6818 + 0.023
0.6588 < p < 0.7048
the nearest value is [0.6592, 0.7044]
Hence the confidence interval for the proportion of students attending a football game is [0.6592, 0.7044]
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Answer:
17/13
Step-by-step explanation:
r(6) = 3(6) - 1 = 17 and s(6) = 2(6) + 1 = 13.
Then (r/s)(6) = 17/13.
Substitute 5 for g so...
5 times 11 =55
My teacher told me to take the number, 3 for example, and break it into ones.
1 1 1
then she said to imagine the ones are going to a dance and need a date. put the one together in groups of two
1-1 1
she then said if there is a one with no date the number is odd