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Furkat [3]
4 years ago
12

WILL GIVE BRAINLIEST

Mathematics
1 answer:
Luda [366]4 years ago
6 0
1A
2C
3A
Give me brainliest
You might be interested in
Nine times the sum of a number and 8 is 7
Sladkaya [172]

this is the equation x+9+8=7

5 0
4 years ago
Tell what each of the residual plots below indicates about the appropriateness of the linear model
ELEN [110]
The closer the points are/more uniform they are to the residual line, the better the fit.  The more skewed and scattered they are, the model is a worse fit.
3 0
3 years ago
I don't really need the answer I just want to understand how to get the answer.
Debora [2.8K]
You use the rules of BEDMAS so start with the brackets -[2(-17)] start with 2*-17 which is -34 then multiply -4*-5=20 so now you have 20-(-17)=37 butttt the question is asking to SIMPLIFY so you combine like terms which adds up to 37
5 0
4 years ago
Read 2 more answers
Which expression is equivalent to 1/3(12x+6x-21)
marin [14]

Answer:

6x-7

Step-by-step explanation:

\frac{1}{3} (12x + 6x -21)

break it into pieces

\frac{1}{3}*12x = 4x

\frac{1}{3}*6x=2x

\frac{1}{3} *-21=-7

put it all together

*since there's no negative in front  of the other numbers except 7 they're positive so you add them*

4x + 2x - 7

simplify

6x - 7

4 0
3 years ago
The Table below gives you The population of Texas since 1970. Find the average rate if change from 1970 to 1090
ruslelena [56]

Answer:

Average rate of change = 0.29 million per year

Step-by-step explanation:

Average rate of change in the population from year 1970 to year 1900 is given by the formula,

Average rate of change = \frac{\text{Population in year 1990-Population in year 1970}}{1990-1970}

                                        = \frac{17-11.2}{1990-1970}

                                        = \frac{5.8}{20}

                                        = 0.29 million per year

Therefore, average rate of change in the population from 1970 to 1990 will be 0.29 million per year.                        

8 0
3 years ago
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