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algol13
3 years ago
15

Consider parallelogram ABCD. If AC¯¯¯¯¯¯¯¯=2x+15 and BD¯¯¯¯¯¯¯¯=5x−12, what does the value of x need to be so that the parallelo

gram is a rectangle?
A: 1
B: -9
C: 9
D: 3/7
Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

9

Step-by-step explanation:

I took the quick check

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2(3x – 4)= -2(x - 2
vesna_86 [32]

Answer:

2(3x-4)=-2(x-2)

6x-8=-2x+4

6x+2x=4+8

8x=12

x=12/8

x=3/2 or x=1.5

8 0
3 years ago
Read 2 more answers
50 POINTS FOR THIS IFBYOU GIVE ME A DECENT ANSWER
defon

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The given equation is in intercept form:

  x/(x-intercept) +y/(y-intercept) = 1

This means the x- and y-intercepts are (4, 0) and (0, -3), respectively. Plot these points and draw the line through them.

3 0
3 years ago
Slope of the line with a figure (picture included)
Crank

Answer:

the rise is 1 and i think the run is negative 2 so the slop should be 1/-2

Step-by-step explanation:

6 0
3 years ago
Yes,I need help with another one of these , the number that got cut off is 24 btw.
V125BC [204]

Since, PS and QR are parallel, we know that <QRP is equal to <RPS.  Therefore, we can solve for y by setting the two equations equal to each other.

5y+14=8y-13

<em>*Subtract 5y from both sides to isolate the variable*</em>

14=3y-13

<em>*Add 13 to both sides*</em>

27=3y

<em>*Divide both sides by 3*</em>

9=y


Now, plug in 9 for y in the equation 8y-13 to find the measure of that angle.

8(9)-13

<RPS=59


Now, the sum of the angles in any triangle is equal to 180 degrees.  We can use this knowledge to set up an equation to solve for x.

3x+2x+1+59=180

<em>*Combine like terms*</em>

5x+60=180

<em>*Subtract 60 from both sides*</em>

5x=120

<em>*Divide both sides by 5*</em>

x=24


Now, we can find <RSP by pluggin 24 in for x.

2(24)+1

48+1

<RSP=49 degrees


Hope this helps!!

3 0
4 years ago
g Farmer Violet wants to enclose one 990 square foot rectangular area of land using fencing. One side will use special fencing c
saw5 [17]

Answer:

Sides of the rectangular area:

x =  30  f

y =  33  f

Step-by-step explanation:

Let´s call   x  and y the sides of the rectangular area

A = x*y  = 990          y  = 990/x

The function cost is:

C = Costs ( sides x)  + costs ( sides y )

Cost of sides x    =  12*x +  10x

Cost of sides y    =  10*y  +  10 *y   =  2*10*y  = 20*y

C = 12*x + 10*x + 20*y =  22*x  + 20*y

The function cost as function of x is:

C(x)  = 22*x + 20*(990/y)  =  22*x  +  19800/x

Tacking derivative on both sides of the equation:

C´(x)  = 22  + [ - 19800/x²]

C´(x) = 0       22  - 19800/x²  =  0

Solving for x

22*x²  - 19800  =  0

22x²  =  19800

x² =  19800/22 =  900

x₁,₂ = ± 30        We dismiss negative root ( we never have negative lenghts)

Then     x =  30 f

And  y  =  990 / 30      y  = 33  

To see if x = 30 is a minimum for function C(x) we evaluate the second derivative.

C´´(x) = 2*x* 19800/x⁴      

C´´ (x) = 39600/x³    so C´´ is always greater than 0 then C (x) has a minimum at x = 30

Sides of the rectangular area are:

x  =  30

y  =  33

6 0
3 years ago
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