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drek231 [11]
3 years ago
8

A block that slides on a rough surface slows down and eventually stops. The reverse process never occurs. That is, a block at re

st never begins to move and accelerate on a rough surface without the action of an external agent. The second situation is forbidden because it would violate:_________.
a) conservation of total energy
b) conservation of momentum
c) the first law of thermodynamics
d) the second law of thermodynamics
e) both the first and second law of thermodynamics
Gracias.
Physics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

d) the second law of thermodynamics

Explanation:

Here we take an example

The entropy represents a measurement of the energy dispersal in the system. Also, the campfire would an entropy example. The burning of the solid wood and then it became the ash, smoke and gases this all would be spread the energy to the outward as compared to the solid fuel

Therefore as per the given statement, the correct option is d.

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If a bowling ball is moving with acceleration of 15 m/s2 and has a mass of 10kg what is the force of the ball as it knocks down
Lina20 [59]

Answer:

150 newtons

Explanation:

F = ma

force = mass * acceleration

the mass is 10 kg, and the accelration is 15 m/s^2

10*15 = 150

the force unit that matches with meters/second and kg is newtons

F =ma

150 newtons = 10 kg * 15 m/s^2

6 0
3 years ago
On a horizontal, linear track lies a cart that has a fan attached to it. The mass of the cart plus fan is 364 g. The cart is pos
mamaluj [8]

Answer:

6.62s

Explanation:

Metric unit conversion:

364 g = 0.364 kg

789 g = 0.789 kg

Starting from rest, the cart takes 4.49 s to travel a distance of 1.43 m. We can use the following equation of motion to calculate the constant acceleration

s = a_1t_1^2/2

a_1 = \frac{2s}{t_1^2} = \frac{2*1.43}{4.49^2} = 0.142 m/s^2

Using Newton's 2nd law, we can calculate the force generated by the fan to push the 0.364 kg cart forward

F = a_1m_1 = 0.142*0.364 = 0.052 N

Now that more mass is added, the new acceleration of the 0.789 kg cart is

a_2 = F/m_2 = 0.052 / 0.789 = 0.065 m/s^2

We can reuse the same equation of motion to calculate the time it takes to travel 1.43 m from rest

s = a_2t_2^2/2

t_2^2 = 2s/a_2 = 2*1.43/0.065 = 43.7

t_2 = \sqrt{43.7} = 6.62s

6 0
4 years ago
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A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boil
Naily [24]

Answer:

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Explanation:

like how do you get this question

5 0
3 years ago
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Find the time it takes for an object dropped from a building and reaches a final velocity of 20 m/s downward?
MrRissso [65]

Answer:

Explanation:

v = at

t = v/a

t = 20 m/s / 9.8 m/s²

t = 2.0408163...

t = 2.0 s

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I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
snow_tiger [21]

Answer:

h

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law[1] of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force.[2] The law was first discovered in 1785 by French physicist Charles-Augustin de Coulomb, hence the name. Coulomb's law was essential to the development of the theory of electromagnetism, maybe even its starting point,[1] as it made it possible to discuss the quantity of electric charge in a meaningful way.[3]

The law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them,[4]

{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}

Here, ke is Coulomb's constant (ke ≈ 8.988×109 N⋅m2⋅C−2),[1] q1 and q2 are the signed magnitudes of the charges, and the scalar r is the distance between the charges.

The force is along the straight line joining the two charges. If the charges have the same sign, the electrostatic force between them is repulsive; if they have different signs, the force between them is attractive.

Being an inverse-square law, the law is analogous to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.[2] Coulomb's law can be used to derive Gauss's law, and vice versa. In the case of a single stationary point charge, the two laws are equivalent, expressing the same physical law in different ways.[5] The law has been tested extensively, and observations have upheld the law on the scale from 10−16 m to 108 m.[5]

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3 years ago
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