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drek231 [11]
3 years ago
8

A block that slides on a rough surface slows down and eventually stops. The reverse process never occurs. That is, a block at re

st never begins to move and accelerate on a rough surface without the action of an external agent. The second situation is forbidden because it would violate:_________.
a) conservation of total energy
b) conservation of momentum
c) the first law of thermodynamics
d) the second law of thermodynamics
e) both the first and second law of thermodynamics
Gracias.
Physics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer:

d) the second law of thermodynamics

Explanation:

Here we take an example

The entropy represents a measurement of the energy dispersal in the system. Also, the campfire would an entropy example. The burning of the solid wood and then it became the ash, smoke and gases this all would be spread the energy to the outward as compared to the solid fuel

Therefore as per the given statement, the correct option is d.

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Which of the following are correct statements about the way an atom is put
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valenc e shell

Explanation:

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3 years ago
find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​
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Answer:

0.02

Explanation:

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\mu_k=\frac {F}{mg}

Substituting F with 2 N, m with 10 kg and g with 9.81 then

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5 0
4 years ago
3–101 It is estimated that 90 percent of an iceberg’s volume is below the surface, while only 10 percent is visible above the su
Artist 52 [7]

Answer:

The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

Explanation:

Given that,

Volume of seawater = 90 % of Volume of iceberg

Volume of visible surface = 10 %

Density of seawater = 1025 kg/m³

We need to calculate the density of the iceberg

Using equilibrium condition

W_{I}=F_{B}

\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g

Put the value into the formula

\rho_{I}\times V_{I}\times g=\rho_{w}\times0.9V_{I}\times g

\rho_{I}=1025\times0.9

\rho_{I}=922.5kg/m^3

We need to calculate the density of the iceberg

Using equilibrium condition

W_{I}=F_{B}

\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g

Put the value into the formula

\rho_{I}\times V_{I}\times g=\rho_{w}\times0.1V_{I}\times g

\rho_{I}=1025\times0.1

\rho_{I}=102.5\ kg/m^3

Hence, The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

5 0
3 years ago
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