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Kazeer [188]
3 years ago
10

Help please I have to turn this in tonight!!

Physics
2 answers:
Svet_ta [14]3 years ago
4 0
False. In a neutral atom, the number of protons is equal to the number of electrons and the number of neutrons has to be determined by an equation.
inna [77]3 years ago
3 0

Answer:

True

Explanation:

i searched it up and well this thing is making me do it up till 20 characters long so yea

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A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

S =20*5 + \frac{1}{2}*(-4)*5^{2}

S =100 + (-2)*25

S =100 - 50

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

V^{2} = 400 - 400

V^{2} = 0

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0
3 years ago
Technician A says that hill assist and hill descent controls are added features to some electronic stability control systems. Te
Pani-rosa [81]

Answer:

Both technicians A and B

Explanation:

Both trailer sway control, hill assist and hill descent controls are additional featires that enhance stability of electronics and their control systems. Majorly, these features track and reduce skidding in electronics, therfore, enhancing electronic system stability. During the process, these newly added features help to automatically apply brakes and direct the sytem where the controller wants to take it.

8 0
3 years ago
. A mass m is traveling at an initial speed of 25.0 m/s. It is brought to rest in a distance of 62.5 m by a net force of 15.0 N.
harkovskaia [24]

Answer:

m = 3 kg

The mass m is 3 kg

Explanation:

From the equations of motion;

s = 0.5(u+v)t

Making t thr subject of formula;

t = 2s/(u+v)

t = time taken

s = distance travelled during deceleration = 62.5 m

u = initial speed = 25 m/s

v = final velocity = 0

Substituting the given values;

t = (2×62.5)/(25+0)

t = 5

Since, t = 5 the acceleration during this period is;

acceleration a = ∆v/t = (v-u)/t

a = (25)/5

a = 5 m/s^2

Force F = mass × acceleration

F = ma

Making m the subject of formula;

m = F/a

net force F = 15.0N

Substituting the values

m = 15/5

m = 3 kg

The mass m is 3 kg

7 0
3 years ago
A cell phone is released from the top with the speed of 10ms what is the speed 3s after?
sergeinik [125]

Answer:

30ms

Explanation:

you need to multiple the 10ms by 3s which gives you 30ms

6 0
3 years ago
How does the theory of relativity explain the gravity exerted by massive objects?
Maslowich

(D)

Explanation:

The more massive an object is, the greater is the curvature that they produce on the space-time around it.

8 0
3 years ago
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