Can some one answer this?<br> il give brainliest to the first correct person

A production process produces 2% defective parts. A sample of nine parts from the production process is selected. What is the pr

Natasha_Volkova [10]

Answer:

a. .0125

Step-by-step explanation:

For each part, there are only two possible outcomes. Either it is defective, or it is not. The probability of a part being defective is independent of any other part. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

2% defective parts.

This means that $p = 0.02$

A sample of nine parts from the production process is selected.

This means that $n = 9$

What is the probability that the sample contains exactly two defective parts?

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{9,2}.(0.02)^{2}.(0.98)^{7} = 0.0125$

0.0125 = 1.25% probability that the sample contains exactly two defective parts. The correct answer is given by option a.

8 0

3 years ago

Point H is the midpoint of side FK. Triangles F G H and K J H are connected at point H. The lengths of sides F H and H K are con

earnstyle [38]

Answer:

the answer would be x=6

to find it you would set 3x-2 equal to 2x+4 and solve because the two sides would be equal if the triangles are congruent

hope this helps :)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the value of the expression 0.5^10/0.5^7

SIZIF [17.4K]

Answer:

The solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

Step-by-step explanation:

Given the expression

$0.5^{10}\div 0.5^7$

Solving

$\frac{0.5^{10}}{0.5^7}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

so

$\frac{0.5^{10}}{0.5^7}=0.5^{10-7}$

$\mathrm{Subtract\:the\:numbers:}\:10-7=3$

$=0.5^3$

$=0.125$ ∵ $0.5^3=0.125$

Therefore, the solution is:

$\frac{0.5^{10}}{0.5^7}=0.125$

7 0

3 years ago

1. If the domain of a function f(x) is the set {10, 20, 30}. What does the information tell you about f-1(x)?

ziro4ka [17]

PART A (1 in diagram)

Each mapping diagram represents a function because none of the elements in the inputs maps on to two different elements in the outputs.

1. The domain of the given function f(x) is the set {10, 20, 30}.

All we can say about

${f}^{ - 1} (x)$

is that, it has a range of {10, 20, 30}.

This is because the domain of a function becomes the range of its inverse function.

2. If the graph of a function f(x) includes the point (3, 0), then the graph of the inverse function ,

${f}^{ - 1} (x)$

will contain the point (0,3).

Reason:The point on the graph of the inverse function is obtained by reflecting the corresponding point on the graph of the function in the line y=x. We just have to swap the coordinates.

In simple terms the domain of the function becomes the range of the inverse function and vice versa.

3. If the first term in an arithmetic sequence is 2.

Then we have a=2.

If the twelfth term is 211, then

$a + 11d = 211...(1)$