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Wewaii [24]
3 years ago
9

Which of the following is equivalent to x^-1/21) -1/2x 2) -√x3) 1/√x4) -1/2x

Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

Option (3) is correct.

Step-by-step explanation:

We need to find the expression that is equivalent to x^{-1/2}.

The property is : x^{-a}=\dfrac{1}{x^a}

Here, a = 1/2

So,

x^{-1/2}=\dfrac{1}{x^{1/2}}

We know that, x^{1/2}=\sqrt{x}

\dfrac{1}{x^{1/2}}=\dfrac{1}{\sqrt{x} }

So, x^{-1/2} is equivalent to \dfrac{1}{\sqrt{x} }

Hence, the correct option is (3).

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Joseph and Sanjay are trying to finish their math homework before their favorite TV show starts. Joseph finishes 2/3 of his prob
kicyunya [14]
The correct answer is Sanjay! :)

Explanation:
Joseph: 2/3
Sanjay: 5/7
2/3 and 5/7
14/21 and 15/21
Therefore, Sanjay is the answer.
5 0
2 years ago
The sum of two consecutive integers is 7. find the numbers
faust18 [17]
X + (x + 1) = 7

2x + 1 (-1) = 7 (-1)

2x = 6

2x/2 = 6/2

x = 3

x +1 = 3 + 1

x + 1 = 4

The two integers are 3, 4

hope this helps
4 0
3 years ago
Read 2 more answers
Which list contains values that are all part of the solution set of the graphed inequality? 2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1.
olya-2409 [2.1K]

The inequality is,

0\leq x\leq 2001.3

we have given that the solution set

2, 1, 3. 9, 4 2001. 3, 4, 0, 2. 6 1. 1, 1. 5, 19. 7, 8. 2 11, 1, 48. 5, 7.

here we have given that all the values of x are positive and

Which is the smallest point in above set?

0

and

Which is the highest point in the above set?

2001.3

Therefore,

we have a=0 and b=2001.2

Our equality lie in a and b

Therefore,

a\leq x\leq b

Plug the value of a and b we get

0\leq x\leq 2001.3

Therefore we get the inequality is,

0\leq x\leq 2001.3

To learn more about the inequality visit:

brainly.com/question/24372553

8 0
2 years ago
Which of the following points lies on the line y=x?​<br>(-4,4)<br>(2,-2)<br>(-4,-4)<br>-2,2
marshall27 [118]
The answer is (-4,-4) because y has to equal x, the first -4 is the x and the second one is the y
7 0
3 years ago
A 6000​-seat theater has tickets for sale at ​$25 and ​$40. How many tickets should be sold at each price for a sellout performa
Lena [83]

Step-by-step explanation:

Let x be the amount of tickets sold for $25 and y be the amount of tickets sold for $40, since there are 6000 seats theatre then;

x+y = 6000 .............. 1

If x tickets cost $25 and y tickets are sold for $40 with total revenue of ​$174,000, then;

25x + 40y = ​174,000................ 2

From 1, x = 6000-y ............ 3

Substitute equation 3 into 2:

25x + 40y = ​174,000.

25(6000-y) + 40y = ​174,000

150,000-25y + 40y = 174,000

150,000+15y = 174,000

15y = 174,000-150,000

15y = 24,000

y = 24,000/15

y = 1600

Substitute y = 1600 into equation 3:

x = 6000-y

x = 6000-1600

x = 4400

<em>Hence 4400 $25 tickets and 1600 $40 tickets must be sold to generate a revenue of $174,000</em>

4 0
3 years ago
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