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ipn [44]
3 years ago
11

OMG PLS— THIS IS DUE AT 8PM—

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

so good

Step-by-step explanation:

so good

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2.) Using any tool (Desmos or by hand on scratch paper) graph the inequality. Select 3 points. One point should
insens350 [35]
The line 6x - 2y = 12 goes through -6 on the y-axis and 2 on the x-axis ie through (0, -6) and (2, 0)
The line will be solid and shaded above (towards the origin)

There are an infinite number of choices for the example points!
Here is my selection.
(0, 0) is in the solution set. 6 x 0 - 2 x 0 = 0 which is less than 12
(5, 0) is not in the solution set. 6 x 5 - 2 x 0 = 30 which is greater than 12
(2, 0) is on the line. 6 x 2 - 2 x 0 = 12
5 0
3 years ago
24x^5-8x^4+12x^3-4x^2 / 4x^2
Margaret [11]

Answer:

The detailed process of simplification is :

Step-by-step explanation:

\frac{24x^{5} - 8x^{4} + 12x^{3} - 4x^{2} }{4x^{2} }

= \frac{24x^{5} }{4x^{2} } - \frac{8x^{4} }{4x^{2} } + \frac{12x^{3} }{4x^{2} } - \frac{4x^{2}  }{4x^{2} } ..........................separate the terms

= 6x^{5-2} - 2x^{4-2} + 3x^{3-2} - 1 ................ subtract the power of x from denominator

= 6x^{3} - 2x^{2} + 3x -1

= 2x^{2}( 3x -1 ) +  (3x -1 )................................... Take  (3x -1 ) common in (6x^{3} - 2x^{2})

=  (3x -1 ) (2x^{2} +1) .......................................Take  (3x -1 ) common in whole equation

3 0
3 years ago
Can someone explain to me how this has multiple answers? I really don't understand! When I did it I only got the first answer. P
Vesna [10]

in \: firt \: quadrant \\ sin \frac{\pi}{4}  =  \frac{ \sqrt{2} }{2}  \\ in \: second \: quadrant \\ sin \frac{3\pi}{4} =  \frac{ \sqrt{2} }{2}  \\ in \: third \: quadrant \:  \\ sin \frac{5\pi}{4}  = \frac{ -  \sqrt{2} }{2}  \\ in \: forth \: quadrant \\  sin \frac{7\pi}{4}  =  - \frac { \sqrt{ 2} }{2}  \\ in \: this \: way \: it \: has \: multiple \: soution

3 0
3 years ago
Find the value of a and b if root3-1/root3+1+ root3+1/root3-1=a+root3 b​
Digiron [165]

Answer:

a=4 and b = 0

Step-by-step explanation:

Given : \dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b

To find, The value of a and b

Solution,

Solving LHS of the given equation,

\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b

Since,

(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2

So,

\dfrac{3+1-2\sqrt 3+3+1+2\sqrt 3}{3-1}=a+\sqrt 3 b\\\\4=a+\sqrt 3 b

or

4+0=a+\sqrt 3 b

On comparing we get :

a = 4 and b = 0

4 0
3 years ago
Write the number name for 44,080,700 in expanded form
Nastasia [14]
Expanded Form:
40,000,000+4,000,000+80,000+700
3 0
3 years ago
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