A circle has a radius of 6 ft.
1 answer:
You might be interested in
Plot the intercepts:
y=-1
x=?
to find the x intercept, you dont solve the equation as it is solved in the slope-intercept form. instead, you simply plug in 0 for y:
0=1/4x-4
0=1/4x-4+4
4=1/4x
4/1/4=1/4x
1/4=0.25
x=16
revise:
y=(0, -1)
x=(16,0)
graph the slope for y=-1/2x-1: start from say point (0,-1)
graph the slope for y=1/4x-4: start from say point (16,0) ; you can just ise the intercept (0,-4) since the graph is diluted small...anyways
the points intersect at (4, -3) so thats the solution to the equations
NOTE: when graphing slopes that are negative either the numerator or the denominator can be graphed negative. so I graphed the first equation with the numerator as the positive and the denominator as the negative : rise= 1 ; run: -2. once i got to the end of the provided graph i started from the -1 y-intercept again and graphed the equation using: rise=-1; run=2
*graphing messes me up, too*
