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Margarita [4]
2 years ago
10

Tyler has two savings accounts that his grandparents opened for him. One of accounts pay 7 % annual interest, whereas the other

pays 9 % annual interest. you have $600 more invested 9% then you invested at 7% , how much do you have invested in each account if the total amount of interest you eam in a year is $118
Mathematics
1 answer:
Dafna11 [192]2 years ago
5 0

Answer:

$400 and $1,000

Step-by-step explanation:

Let us assume the x be the amount invested in 7% account

And, 600 + x be the amount invested in 9% account

Now the equation is

7x% + 9%(600 + x) = $118

0.07x + 54 + 0.09x = $118

0.16x = $118 -$54

0.16x = $64

x = $400

And, the other one is = $400 + $600 = $1,000

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⚠️HURRY WHORTH 30 points ⚠️Charlie bikes 9 miles everyday which equation models the situation
astraxan [27]

Answer:

C.9d=m

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which value of x satisfies both -9x + 4y = 8 and -3x − y = 4 given the same value of y?
liq [111]

Answer:

C

Step-by-step explanation:

Since y will have same value, y doesn't really matter. Thus,

We can solve for y in the 2nd equation as:

-3x - y = 4

-3x - 4 = y

Now we can plug it into the first and solve for x:

-9x + 4y = 8

-9x + 4(-3x - 4) = 8

-9x - 12x - 16 = 8

-21x = 8 + 16

-21x = 24

x = 24/-21

x = -8/7

Correct answer is C.

4 0
3 years ago
Read 2 more answers
18/90 in simplest form
mafiozo [28]
18/90
Divide by the common factor of 18 and 90, 9.
(18/9) / (90/9)
2/10
Divide top and bottom by 2

1/5

Hope this helps :)
7 0
3 years ago
Read 2 more answers
I need help on this question !!!
viktelen [127]

Answer:

C is the right answer I think

5 0
2 years ago
Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant
ludmilkaskok [199]
The complete question in the attached figure

we have that
tan a=7/24    a----> III quadrant
cos b=-12/13   b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

8 0
3 years ago
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