3 years ago

Select the correct answer from each drop-down menu.

Mathematics

2 answers:

VikaD [51]3 years ago

6 0

Answer:

will not have. 23. more to save.

Step-by-step explanation:

Nana76 [90]3 years ago

4 0

Answer:

she will not have enough money

she will have 23 more to save

Step-by-step explanation:

got it right on plato

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Answer:

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Step-by-step explanation:

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3 years ago

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kayla took $36.75 to the state fair. each ticket in the fair cost x dollars. kayla bought 3 tickets. write an expression that re

Gennadij [26K]

F(x)=y=the amount of money, in dollars , that Kad had after she bought the tickets.
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3 years ago

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

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3 years ago

(01.02) kim earns $30 for babysitting on friday nights. she makes an average of $1.25 in tips per hour. write the function of ki

defon

Y = 1.25x + 30 <== ur function

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3 years ago

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dybincka [34]

The answer is 6/46656
$\frac{6}{46656}$

good luck

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3 years ago